Barium Bohr model

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In the barium Bohr model, the nucleus is composed of 56 protons and 81 neutrons. Circling this nucleus are six electron shells, accommodating a total of 56 electrons.

To draw the barium Bohr model, represent the 56 protons, 81 neutrons, and 56 electrons. Start by sketching the nucleus, and then illustrate the six electron shells. The first two shells should contain 2 and 8 electrons, respectively, while the third and fourth shells hold 18 electrons each. The fifth shell accommodates 8 electrons, and the sixth shell has the remaining 2 electrons.

Steps

Write protons, neutrons, and electrons of barium atom

Barium has 56 protons, 81 neutrons, and 56 electrons.

Learn how to find: Barium protons neutrons electrons

Draw nucleus of barium atom

The nucleus of a barium atom contains 56 protons and 81 neutrons. So draw the nucleus of strontium atom as follows:

Now in the next step, draw the 1^st electron shell and start marking electrons.

Draw 1^st electron shell

Remember that we have a total of 56 electrons.

The 1^st electron shell (containing s subshell) can hold up to a maximum of 2 electrons. So draw the 1^st electron shell as follows:

In the above image, 1 represents the 1^st electron shell that contains 1s subshell. And the green color represents the number of electrons in that subshell. This means that the 1^st electron shell has a total of 2 electrons.

Since we have already used 2 electrons in the 1^st electron shell, now we have 56 – 2 = 54 electrons left. So in the next step, we have to draw the 2^nd electron shell.

Draw 2^nd electron shell

The 2^nd electron shell (containing s subshell and p subshell) can hold up to a maximum of 8 electrons. So draw the 2^nd electron shell as follows:

In the above image, 2 represents the 2^nd electron shell that contains 2s and 2p subshells. And the green and orange color represents the number of electrons in that subshell. This means that the 2^nd electron shell has a total of 8 electrons.

Now we have already used 10 electrons in 1^st and 2^nd electron shells, so we have 54 – 10 = 44 electrons left. So in the next step, we have to draw the 3^rd electron shell.

Draw 3^rd electron shell

The 3^rd electron shell (containing s subshell, p subshell, and d subshell) can hold up to a maximum of 18 electrons. So draw the 3^rd electron shell as follows:

In the above image, 3 represents the 3^rd electron shell that contains 3s, 3p, and 3d subshells. And the green, orange, and pink color represents the number of electrons in that subshell. This means that the 3^rd electron shell has a total of 18 electrons.

Now we have already used 28 electrons in 1^st, 2^nd, and 3^rd electron shells, so we have 56 – 28 = 28 electrons left. So in the next step, we have to draw the 4^th electron shell.

Draw 4^th electron shell

The 4^th electron shell (containing s subshell, p subshell, d subshell, and f subshell) can hold up to a maximum of 32 electrons. So draw the 4^th electron shell as follows:

In the above image, 4 represents the 4^th electron shell that contains 4s, 4p, and 4d subshells. And the green, orange, and pink color represents the number of electrons in that subshell. This means that the 4^th electron shell has a total of 18 electrons.

The 4^th electron shell contains only 4s, 4p, and 4d subshells, and not a 4f subshell. This is because according to the aufbau principle, the 5s subshell is filled first and then 4d, 5p, 6s… and so on.

Now we have already used 46 electrons in 1^st, 2^nd, 3^rd, and 4^th electron shells, so we have 56 – 46 = 10 electrons left. So in the next step, we have to draw the 5^th electron shell.

Draw 5^th electron shell

The 5^th electron shell can hold up to a maximum of 50 electrons. So draw the 5^th electron shell as follows:

In the above image, 5 represents the 5^th electron shell that contains 5s and 5p subshells. And the green and orange color represents the number of electrons in that subshell. This means that the 5^th electron shell has a total of 8 electrons.

The 5^th electron shell contains only 5s and 5p subshells, and not 5d and 5f subshells. This is because according to the aufbau principle, the 6s subshell is filled first and then 4f, 5d, 6p… and so on.

Now we have already used 54 electrons in 1^st, 2^nd, 3^rd, 4^th, and 5^th electron shells, so we have 56 – 54 = 2 electrons left. So in the next step, we have to draw the 6^th electron shell.

Draw 6^th electron shell

The 6^th electron shell can hold up to a maximum of 72 electrons. So draw the 6^th electron shell as follows:

In the above image, 6 represents the 6^th electron shell that contains 6s subshell. And the green color represents the number of electrons in that subshell. This means that the 6^th electron shell has a total of 2 electrons.

That’s it! This is the final Bohr model of barium atom as we have used all 56 electrons: 2 electrons in the 1^st electron shell, 8 electrons in the 2^nd electron shell, 18 electrons in the 3^rd electron shell, 18 electrons in the 4^th electron shell, 8 electrons in the 5^th electron shell, and 2 electrons in the 6^th electron shell.

Next: Francium Bohr model

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Related

• Barium

More topics

• Barium electron configuration
• Barium orbital diagram
• Barium protons neutrons electrons
• Barium valence electrons

External links

• File:56 barium (Ba) enhanced Bohr model.png – Wikimedia Commons
• What is the Bohr model for Barium? – Chemistry QnA – Topblogtenz
• Chemical Elements.com – Barium (Ba) – Chemical Elements.com
• Bohr Diagrams of Atoms and Ions – Chemistry LibreTexts
• Barium (Ba) – Periodic Table – ChemicalAid
• Barium (Ba) – Periodic Table (Element Information & More) – Periodic Table Guide