# Force Equation | Problems (With Solutions)

Force (N) is equal to mass (kg) times acceleration (m/s2). Using the equation of force: F = m × a, the value of force acting on an object can be calculated.

Let’s solve some problems based on this equation, so you’ll get a clear idea.

## Force Practice Problems

Problem 1: Calculate the force required to accelerate a 5 kg box at the rate of 10 m/s2.

Solution:

Given data:
Mass of a box, m = 5 kg
Acceleration of a box, a = 10 m/s2
Force acting on a box, F = ?

Using the equation of force,
F = m × a
F = 5 × 10
F = 50 N

Therefore, the force required to accelerate a 5 kg box at the rate of 10 m/s2 is 50 N.

Problem 2: A football of mass 450 gm is accelerating at the rate of 20 m/s2. How much force is acting on a football?

Solution:

Given data:
Mass of a football, m = 450 gm = 0.45 kg
Acceleration of a football, a = 20 m/s2
Force acting on a football, F = ?

Using the equation of force,
F = m × a
F = 0.45 × 20
F = 9 N

Therefore, the force acting on a football is 9 N.

Problem 3: Calculate the value of force acting on a 2 kg bowling ball, which is accelerating further at the rate of 18 m/s2.

Solution:

Given data:
Mass of a bowling ball, m = 2 kg
Acceleration of a bowling ball, a = 18 m/s2
Force acting on a bowling ball, F = ?

Using the equation of force,
F = m × a
F = 2 × 18
F = 36 N

Therefore, the value of force acting on a bowling ball is 36 N.

Problem 4: When a rubber tyre of mass 1 kg accelerates further at the rate of 6 m/s2, there is some force acting on it. What is the value of force acting on a rubber tyre?

Solution:

Given data:
Mass of a rubber tyre, m = 1 kg
Acceleration of a rubber tyre, a = 6 m/s2
Force acting on a rubber tyre, F = ?

Using the equation of force,
F = m × a
F = 1 × 6
F = 6 N

Therefore, the value of force acting on a rubber tyre is 6 N.

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