
The force equation states that the force (F) acting on an object is equal to the product of its mass (m) and acceleration (a). Mathematically represented as F = m × a, this equation is used to calculate the amount of force exerted on an object.
Practice problems
Problem #1
Determine the force required to accelerate a 5 kg box at the rate of 10 m/s2.
Solution
Given data:
- Force acting on a box, F = ?
- Mass of a box, m = 5 kg
- Acceleration of a box, a = 10 m/s2
Applying the formula:
- F = m × a
- F = 5 × 10
- F = 50 N
Therefore, the force required to accelerate a 5 kg box at the rate of 10 m/s2 is 50 N.
Problem #2
What is the force acting on a football with a mass of 450 grams when it is accelerating at a rate of 20 m/s2?
Solution
Given data:
- Force acting on a football, F = ?
- Mass of a football, m = 450 gm = 0.45 kg
- Acceleration of a football, a = 20 m/s2
Applying the formula:
- F = m × a
- F = 0.45 × 20
- F = 9 N
Therefore, the force acting on a football is 9 N.
Problem #3
Calculate the force acting on a 2 kg bowling ball that is experiencing an acceleration of 18 m/s2.
Solution
Given data:
- Force acting on a bowling ball, F = ?
- Mass of a bowling ball, m = 2 kg
- Acceleration of a bowling ball, a = 18 m/s2
Applying the formula:
- F = m × a
- F = 2 × 18
- F = 36 N
Therefore, the value of force acting on a bowling ball is 36 N.
Problem #4
If a rubber tire with a mass of 1 kg accelerates at a rate of 6 m/s2, what is the magnitude of the force acting on it?
Solution
Given data:
- Mass of a rubber tire, m = 1 kg
- Acceleration of a rubber tire, a = 6 m/s2
- Force acting on a rubber tire, F = ?
Applying the formula:
- F = m × a
- F = 1 × 6
- F = 6 N
Therefore, the value of force acting on a rubber tire is 6 N.
Related
More topics
- Force equation
- Normal force equation
- Net force formula
- Applied force formula
- Magnetic force equation
- Centripetal force equation
- Centrifugal force equation
- Spring force equation
- Tension force formula
- Electric force equation