Gold Bohr model

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The gold Bohr model depicts a nucleus with 79 protons and 118 neutrons. Orbiting this nucleus are six electron shells, housing a total of 79 electrons.

To draw the gold Bohr model, outline the 79 protons, 118 neutrons, and 79 electrons. Start by illustrating the nucleus, and then draw the six electron shells. The first five shells should contain 2, 8, 18, 32, and 18 electrons, respectively, while the sixth shell holds the remaining 1 electron.

Steps

Write protons, neutrons, and electrons of gold atom

Gold has 79 protons, 118 neutrons, and 79 electrons.

Learn how to find: Gold protons neutrons electrons

Draw nucleus of gold atom

The nucleus of a gold atom contains 79 protons and 118 neutrons. So draw the nucleus of gold atom as follows:

Now in the next step, draw the 1^st electron shell and start marking electrons.

Draw 1^st electron shell

Remember that we have a total of 79 electrons.

The 1^st electron shell (containing s subshell) can hold up to a maximum of 2 electrons. So draw the 1^st electron shell as follows:

In the above image, 1 represents the 1^st electron shell that contains 1s subshell. And the green color represents the number of electrons in that subshell. This means that the 1^st electron shell has a total of 2 electrons.

Since we have already used 2 electrons in the 1^st electron shell, now we have 79 – 2 = 77 electrons left. So in the next step, we have to draw the 2^nd electron shell.

Draw 2^nd electron shell

The 2^nd electron shell (containing s subshell and p subshell) can hold up to a maximum of 8 electrons. So draw the 2^nd electron shell as follows:

In the above image, 2 represents the 2^nd electron shell that contains 2s and 2p subshells. And the green and orange color represents the number of electrons in that subshell. This means that the 2^nd electron shell has a total of 8 electrons.

Now we have already used 10 electrons in 1^st and 2^nd electron shells, so we have 79 – 10 = 69 electrons left. So in the next step, we have to draw the 3^rd electron shell.

Draw 3^rd electron shell

The 3^rd electron shell (containing s subshell, p subshell, and d subshell) can hold up to a maximum of 18 electrons. So draw the 3^rd electron shell as follows:

In the above image, 3 represents the 3^rd electron shell that contains 3s, 3p, and 3d subshells. And the green, orange, and pink color represents the number of electrons in that subshell. This means that the 3^rd electron shell has a total of 18 electrons.

Now we have already used 28 electrons in 1^st, 2^nd, and 3^rd electron shells, so we have 79 – 28 = 51 electrons left. So in the next step, we have to draw the 4^th electron shell.

Draw 4^th electron shell

The 4^th electron shell (containing s subshell, p subshell, d subshell, and f subshell) can hold up to a maximum of 32 electrons. So draw the 4^th electron shell as follows:

In the above image, 4 represents the 4^th electron shell that contains 4s, 4p, 4d, and 4f subshells. And the green, orange, pink, and blue color represents the number of electrons in that subshell. This means that the 4^th electron shell has a total of 32 electrons.

Now we have already used 60 electrons in 1^st, 2^nd, 3^rd, and 4^th electron shells, so we have 79 – 60 = 19 electrons left. So in the next step, we have to draw the 5^th electron shell.

Draw 5^th electron shell

The 5^th electron shell can hold up to a maximum of 50 electrons. So draw the 5^th electron shell as follows:

In the above image, 5 represents the 5^th electron shell that contains 5s, 5p, and 5d subshells. And the green, orange, and pink color represents the number of electrons in that subshell. This means that the 5^th electron shell has a total of 18 electrons.

The 5^th electron shell contains only 5s, 5p, and 5d subshells, and not a 5f subshell. This is because according to the aufbau principle, the 6s subshell is filled first and then 4f, 5d, 6p… and so on.

Now we have already used 78 electrons in 1^st, 2^nd, 3^rd, 4^th, and 5^th electron shells, so we have 79 – 78 = 1 electron left. So in the next step, we have to draw the 6^th electron shell.

Draw 6^th electron shell

The 6^th electron shell can hold up to a maximum of 72 electrons. So draw the 6^th electron shell as follows:

In the above image, 6 represents the 6^th electron shell that contains 6s subshell. And the green color represents the number of electrons in that subshell. This means that the 6^th electron shell has a total of 1 electron.

That’s it! This is the final Bohr model of gold atom as we have used all 79 electrons: 2 electrons in the 1^st electron shell, 8 electrons in the 2^nd electron shell, 18 electrons in the 3^rd electron shell, 32 electrons in the 4^th electron shell, 18 electrons in the 5^th electron shell, and 1 electron in the 6^th electron shell.

Next: Mercury Bohr model

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Related

• Gold

More topics

• Gold protons neutrons electrons

External links

• File:79 gold (Au) enhanced Bohr model.png – Wikimedia Commons
• Chemical Elements.com – Gold (Au) – Chemical Elements.com
• How can you determine the Bohr diagram of gold? – Gold
• Gold Bohr Diagram | Science – ShowMe
• Gold Bohr Model – How to draw Bohr diagram for Gold (Au)? – Topblogtenz
• Atomic Structure of Gold – Sciencing
• Gold (Au) – Periodic Table – ChemicalAid
• Bohr Diagrams of Atoms and Ions – Chemistry LibreTexts