Mass (m) is equal to the product of density (ρ) and the volume (v). Using the formula of mass: m = ρ × v, the value of mass of an object can be calculated.
Let’s solve some problems based on this formula, so you’ll get a clear idea.
Mass Practice Problems
Problem 1: Calculate the mass of a steel, if the density of a steel is 8050 kg/m3 and the volume of a steel is 0.012 m3.
Solution:
Given data:
Mass of a steel, m = ?
Density of a steel, ρ = 8050 kg/m3
Volume of a steel, v = 0.012 m3
Using the formula of mass,
m = ρ × v
m = 8050 × 0.012
m = 96.6 kg
Therefore, the mass of a steel is 96.6 kg.
Problem 2: If the density of a diamond is 3510 kg/m3 and the volume of a diamond is 0.005 m3, then calculate the mass of a diamond.
Solution:
Given data:
Density of a diamond, ρ = 3510 kg/m3
Volume of a diamond, v = 0.005 m3
Mass of a diamond, m = ?
Using the formula of mass,
m = ρ × v
m = 3510 × 0.005
m = 17.55 kg
Therefore, the mass of a diamond is 17.55 kg.
Problem 3: The density of a silver is 10497 kg/m3 and the volume of a silver is 0.008 m3. Calculate the mass of a silver.
Solution:
Given data:
Density of a silver, ρ = 10497 kg/m3
Volume of a silver, v = 0.008 m3
Mass of a silver, m = ?
Using the formula of mass,
m = ρ × v
m = 10497 × 0.008
m = 83.97 kg
Therefore, the mass of a silver is 83.97 kg.
Problem 4: Find the mass of an ice having a density 917 kg/m3 and the volume 0.007 m3.
Solution:
Given data:
Mass of ice, m = ?
Density of ice, ρ = 917 kg/m3
Volume of ice, v = 0.007 m3
Using the formula of mass,
m = ρ × v
m = 917 × 0.007
m = 6.41 kg
Therefore, the mass of an ice is 6.41 kg.
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Related:
- Free Fall Equation
- Air Resistance Formula
- Terminal Velocity Equation
- Gravity Equation
- Inertia Formula
- Acceleration Formula
- Momentum Equation
- Velocity Formula
- Pressure Equation
- Kinematic Equations
- Friction Equation
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