# Newton’s Second Law Equation | Problems (With Solutions)

Newton’s second law equation states that the acceleration of an object directly depends upon the net force (Fnet) applied on it and inversely depends upon the mass (m) of an object. Here’s the equation of newton’s second law: a = Fnet/m

Let’s solve some problems based on this equation, so you’ll get a clear idea.

## Newton’s Second Law Practice Problems

Problem 1: A box of mass 2 kg slowly accelerates forward when a 4 N of net force is applied on it. At what rate does the box accelerate forward?

Solution:

Given data:
Mass of a box, m = 2 kg
Net force applied on a box, Fnet = 4 N
Acceleration of a box, a = ?

Using the equation of newton’s second law,
a = Fnet/m
a = 4/2
a = 2 m/s2

Therefore, a box accelerates forward at the rate of 2 m/s2.

Problem 2: Calculate the acceleration of a 12 kg wooden cart, when a 6 N of net force is applied on it.

Solution:

Given data:
Mass of a wooden cart, m = 12 kg
Net force applied on a wooden cart, Fnet = 6 N
Acceleration of a wooden cart, a = ?

Using the equation of newton’s second law,
a = Fnet/m
a = 6/12
a = 0.5 m/s2

Therefore, the acceleration of a wooden cart is 0.5 m/s2.

Problem 3: A 180 N of net force is applied on a 100 kg wagon. Calculate the acceleration of the wagon.

Solution:

Given data:
Net force applied on a wagon, Fnet = 180 N
Mass of a wagon, m = 100 kg
Acceleration of a wagon, a = ?

Using the equation of newton’s second law,
a = Fnet/m
a = 180/100
a = 1.8 m/s2

Therefore, the acceleration of a wagon is 1.8 m/s2.

Problem 4: What is the acceleration of a 400 kg horse cart when a 800 N of net force is applied on it?

Solution:

Given data:
Acceleration of a horse cart, a = ?
Mass of a horse cart, m = 400 kg
Net force applied on a horse cart, Fnet = 800 N

Using the equation of newton’s second law,
a = Fnet/m
a = 800/400
a = 2 m/s2

Therefore, the acceleration of a horse cart is 2 m/s2.

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