Platinum Bohr model

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In the platinum Bohr model, the nucleus comprises 78 protons and 117 neutrons. Surrounding this nucleus are six electron shells, accommodating a total of 78 electrons.

To draw the platinum Bohr model, represent the 78 protons, 117 neutrons, and 78 electrons. Begin by sketching the nucleus, and then draw the six electron shells. The first five shells should contain 2, 8, 18, 32, and 17 electrons, respectively, while the sixth shell holds the remaining 1 electron.

Steps

Write protons, neutrons, and electrons of platinum atom

Platinum has 78 protons, 117 neutrons, and 78 electrons.

Learn how to find: Platinum protons neutrons electrons

Draw nucleus of platinum atom

The nucleus of a platinum atom contains 78 protons and 117 neutrons. So draw the nucleus of platinum atom as follows:

Now in the next step, draw the 1^st electron shell and start marking electrons.

Draw 1^st electron shell

Remember that we have a total of 78 electrons.

The 1^st electron shell (containing s subshell) can hold up to a maximum of 2 electrons. So draw the 1^st electron shell as follows:

In the above image, 1 represents the 1^st electron shell that contains 1s subshell. And the green color represents the number of electrons in that subshell. This means that the 1^st electron shell has a total of 2 electrons.

Since we have already used 2 electrons in the 1^st electron shell, now we have 78 – 2 = 76 electrons left. So in the next step, we have to draw the 2^nd electron shell.

Draw 2^nd electron shell

The 2^nd electron shell (containing s subshell and p subshell) can hold up to a maximum of 8 electrons. So draw the 2^nd electron shell as follows:

In the above image, 2 represents the 2^nd electron shell that contains 2s and 2p subshells. And the green and orange color represents the number of electrons in that subshell. This means that the 2^nd electron shell has a total of 8 electrons.

Now we have already used 10 electrons in 1^st and 2^nd electron shells, so we have 78 – 10 = 68 electrons left. So in the next step, we have to draw the 3^rd electron shell.

Draw 3^rd electron shell

The 3^rd electron shell (containing s subshell, p subshell, and d subshell) can hold up to a maximum of 18 electrons. So draw the 3^rd electron shell as follows:

In the above image, 3 represents the 3^rd electron shell that contains 3s, 3p, and 3d subshells. And the green, orange, and pink color represents the number of electrons in that subshell. This means that the 3^rd electron shell has a total of 18 electrons.

Now we have already used 28 electrons in 1^st, 2^nd, and 3^rd electron shells, so we have 78 – 28 = 50 electrons left. So in the next step, we have to draw the 4^th electron shell.

Draw 4^th electron shell

The 4^th electron shell (containing s subshell, p subshell, d subshell, and f subshell) can hold up to a maximum of 32 electrons. So draw the 4^th electron shell as follows:

In the above image, 4 represents the 4^th electron shell that contains 4s, 4p, 4d, and 4f subshells. And the green, orange, pink, and blue color represents the number of electrons in that subshell. This means that the 4^th electron shell has a total of 32 electrons.

Now we have already used 60 electrons in 1^st, 2^nd, 3^rd, and 4^th electron shells, so we have 78 – 60 = 18 electrons left. So in the next step, we have to draw the 5^th electron shell.

Draw 5^th electron shell

The 5^th electron shell can hold up to a maximum of 50 electrons. So draw the 5^th electron shell as follows:

In the above image, 5 represents the 5^th electron shell that contains 5s, 5p, and 5d subshells. And the green, orange, and pink color represents the number of electrons in that subshell. This means that the 5^th electron shell has a total of 17 electrons.

The 5^th electron shell contains only 5s, 5p, and 5d subshells, and not a 5f subshell. This is because according to the aufbau principle, the 6s subshell is filled first and then 4f, 5d, 6p… and so on.

Now we have already used 77 electrons in 1^st, 2^nd, 3^rd, 4^th, and 5^th electron shells, so we have 78 – 77 = 1 electron left. So in the next step, we have to draw the 6^th electron shell.

Note 1: One partially filled 5d subshell is more stable than one empty 5d subshell. That’s why the 5d subshell has nine electrons (instead of eight electrons). And the 6s subshell has one electron (instead of two electrons).

Note 2: A partially filled 6s subshell is more stable than an empty 6s subshell. That’s why the 6s subshell has one electron (instead of zero electrons). And the 5d subshell has nine electrons (instead of ten electrons).

For a detailed explanation, check the orbital diagram of platinum.

Draw 6^th electron shell

The 6^th electron shell can hold up to a maximum of 72 electrons. So draw the 6^th electron shell as follows:

In the above image, 6 represents the 6^th electron shell that contains 6s subshell. And the green color represents the number of electrons in that subshell. This means that the 6^th electron shell has a total of 1 electron.

That’s it! This is the final Bohr model of platinum atom as we have used all 78 electrons: 2 electrons in the 1^st electron shell, 8 electrons in the 2^nd electron shell, 18 electrons in the 3^rd electron shell, 32 electrons in the 4^th electron shell, 17 electrons in the 5^th electron shell, and 1 electron in the 6^th electron shell.

Next: Gold Bohr model

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Related

• Platinum

More topics

• Platinum orbital diagram
• Platinum protons neutrons electrons

External links

• File:78 platinum (Pt) enhanced Bohr model.png – Wikimedia Commons
• Chemical Elements.com – Platinum (Pt) – Chemical Elements.com
• What is the Bohr model for Platinum? – Topblogtenz
• Platinum (Pt) – Periodic Table – ChemicalAid
• [Grade 9 Chemistry] How do I draw a Bohr-Rutherford diagram of a Platinum atom? – Reddit