Samarium Bohr model

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The samarium Bohr model depicts a nucleus with 62 protons and 88 neutrons. Orbiting this nucleus are six electron shells, housing a total of 62 electrons.

To draw the samarium Bohr model, outline the 62 protons, 88 neutrons, and 62 electrons. Start by illustrating the nucleus, and then draw the six electron shells. The first five shells should contain 2, 8, 18, 24, and 8 electrons, respectively, while the sixth shell holds the remaining 2 electrons.

Steps

Write protons, neutrons, and electrons of samarium atom

Samarium has 62 protons, 88 neutrons, and 62 electrons.

Learn how to find: Samarium protons neutrons electrons

Draw nucleus of samarium atom

The nucleus of a samarium atom contains 62 protons and 88 neutrons. So draw the nucleus of samarium atom as follows:

Now in the next step, draw the 1^st electron shell and start marking electrons.

Draw 1^st electron shell

Remember that we have a total of 62 electrons.

The 1^st electron shell (containing s subshell) can hold up to a maximum of 2 electrons. So draw the 1^st electron shell as follows:

In the above image, 1 represents the 1^st electron shell that contains 1s subshell. And the green color represents the number of electrons in that subshell. This means that the 1^st electron shell has a total of 2 electrons.

Since we have already used 2 electrons in the 1^st electron shell, now we have 62 – 2 = 60 electrons left. So in the next step, we have to draw the 2^nd electron shell.

Draw 2^nd electron shell

The 2^nd electron shell (containing s subshell and p subshell) can hold up to a maximum of 8 electrons. So draw the 2^nd electron shell as follows:

In the above image, 2 represents the 2^nd electron shell that contains 2s and 2p subshells. And the green and orange color represents the number of electrons in that subshell. This means that the 2^nd electron shell has a total of 8 electrons.

Now we have already used 10 electrons in 1^st and 2^nd electron shells, so we have 62 – 10 = 52 electrons left. So in the next step, we have to draw the 3^rd electron shell.

Draw 3^rd electron shell

The 3^rd electron shell (containing s subshell, p subshell, and d subshell) can hold up to a maximum of 18 electrons. So draw the 3^rd electron shell as follows:

In the above image, 3 represents the 3^rd electron shell that contains 3s, 3p, and 3d subshells. And the green, orange, and pink color represents the number of electrons in that subshell. This means that the 3^rd electron shell has a total of 18 electrons.

Now we have already used 28 electrons in 1^st, 2^nd, and 3^rd electron shells, so we have 62 – 28 = 34 electrons left. So in the next step, we have to draw the 4^th electron shell.

Draw 4^th electron shell

The 4^th electron shell (containing s subshell, p subshell, d subshell, and f subshell) can hold up to a maximum of 32 electrons. So draw the 4^th electron shell as follows:

In the above image, 4 represents the 4^th electron shell that contains 4s, 4p, 4d, and 4f subshells. And the green, orange, pink, and blue color represents the number of electrons in that subshell. This means that the 4^th electron shell has a total of 24 electrons.

In the 4^th electron shell, the 4f subshell has only six electrons. This is because according to the aufbau principle, the 5s subshell is filled first and then 4d, 5p, 6s… and so on.

Now we have already used 52 electrons in 1^st, 2^nd, 3^rd, and 4^th electron shells, so we have 62 – 52 = 10 electrons left. So in the next step, we have to draw the 5^th electron shell.

Still have a question: Why does the 4f subshell have only six electrons?

Let’s draw the orbital diagram of samarium, and find the answer to the above question.

Answer: Once the 6s subshell is completely filled, then only we can mark electrons in the 4f subshell. That’s why in the 4^th electron shell, the 4f subshell has only six electrons.

Draw 5^th electron shell

The 5^th electron shell can hold up to a maximum of 50 electrons. So draw the 5^th electron shell as follows:

In the above image, 5 represents the 5^th electron shell that contains 5s and 5p subshells. And the green and orange color represents the number of electrons in that subshell. This means that the 5^th electron shell has a total of 8 electrons.

The 5^th electron shell contains only 5s and 5p subshells, and not 5d and 5f subshells. This is because according to the aufbau principle, the 6s subshell is filled first and then 4f, 5d, 6p… and so on.

Now we have already used 60 electrons in 1^st, 2^nd, 3^rd, 4^th, and 5^th electron shells, so we have 62 – 60 = 2 electrons left. So in the next step, we have to draw the 6^th electron shell.

Draw 6^th electron shell

The 6^th electron shell can hold up to a maximum of 72 electrons. So draw the 6^th electron shell as follows:

In the above image, 6 represents the 6^th electron shell that contains 6s subshell. And the green color represents the number of electrons in that subshell. This means that the 6^th electron shell has a total of 2 electrons.

That’s it! This is the final Bohr model of samarium atom as we have used all 62 electrons: 2 electrons in the 1^st electron shell, 8 electrons in the 2^nd electron shell, 18 electrons in the 3^rd electron shell, 24 electrons in the 4^th electron shell, 8 electrons in the 5^th electron shell, and 2 electrons in the 6^th electron shell.

Next: Europium Bohr model

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Related

• Samarium

More topics

• Samarium electron configuration
• Samarium protons neutrons electrons

External links

• File:62 samarium (Sm) enhanced Bohr model.png – Wikimedia Commons
• What is the Bohr model for Samarium? – Topblogtenz
• Chemical Elements.com – Samarium (Sm) – Chemical Elements.com
• Samarium (Sm) – Periodic Table – ChemicalAid