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Mass quantifies the amount of matter an object possesses. It is an intrinsic characteristic of an object and remains constant regardless of its location. The kilogram (kg) serves as the standard unit of mass, commonly used to express the mass of different objects. For example, the mass of a textbook might be measured as 1.5 kilograms, while the mass of a car could be several thousand kilograms.
Examples
Everyday objects
| Masses of everyday objects | |
|---|---|
| Book | ~300–600 g |
| Coffee cup | ~250–400 g |
| Mobile phone | ~150–250 g |
| Tennis ball | 55–60 g |
| Flower petal | ~0.01–0.05 g |
| Pencil | ~5–10 g |
| Laptop | ~1,000–2,500 g |
| Golf ball | ~45–50 g |
| Cricket ball | 155 g |
| Spoon | ~25–35 g |
| Soccer ball | 400–450 g |
| DSLR camera | ~1,200–1,800 g |
| Wristwatch | ~30–60 g |
| Volleyball | 260–280 g |
| TV remote | ~70–140 g |
Note: The mass values provided above for everyday objects are approximate and intended to offer a general idea. Actual mass may vary depending on factors such as size, material composition, and product variations. For precise measurements, refer to product specifications or use appropriate measuring instruments.
Celestial objects
| Masses of celestial bodies in the Solar System | |
|---|---|
| Sun | 1.989 × 1030 kg |
| Mercury | 3.285 × 1023 kg |
| Venus | 4.867 × 1024 kg |
| Earth | 5.972 × 1024 kg |
| Moon | 7.342 × 1022 kg |
| Mars | 6.39 × 1023 kg |
| Deimos (moon of Mars) | 1.4762 × 1015 kg |
| Phobos (moon of Mars) | ~1.0659 × 1016 kg |
| Jupiter | 1.898 × 1027 kg |
| Ganymede (moon of Jupiter) | 1.4819 × 1023 kg |
| Io (moon of Jupiter) | 8.94 × 1022 kg |
| Europa (moon of Jupiter) | 4.80 × 1022 kg |
| Callisto (moon of Jupiter) | 1.076 × 1023 kg |
| Saturn | 5.683 × 1026 kg |
| Titan (moon of Saturn) | 1.345 × 1023 kg |
| Rhea (moon of Saturn) | 2.306 × 1021 kg |
| Iapetus (moon of Saturn) | 1.806 × 1021 kg |
| Dione (moon of Saturn) | 1.095 × 1021 kg |
| Tethys (moon of Saturn) | 6.174 × 1020 kg |
| Uranus | 8.681 × 1025 kg |
| Oberon (moon of Uranus) | 3.076 × 1021 kg |
| Titania (moon of Uranus) | 3.52 × 1021 kg |
| Umbriel (moon of Uranus) | 1.275 × 1021 kg |
| Ariel (moon of Uranus) | 1.27 × 1021 kg |
| Miranda (moon of Uranus) | 6.4 × 1019 kg |
| Puck (moon of Uranus) | 2.9 × 1018 kg |
| Neptune | 1.024 × 1026 kg |
| Triton (moon of Neptune) | 2.139 × 1022 kg |
| Proteus (moon of Neptune) | 4.4 × 1019 kg |
| Nereid (moon of Neptune) | 3.1 × 1019 kg |
| Larissa (moon of Neptune) | 4.2 × 1018 kg |
| Galatea (moon of Neptune) | 2.12 × 1018 kg |
| Despina (moon of Neptune) | 2.2 × 1018 kg |
| Pluto (dwarf planet) | 1.309 × 1022 kg |
Note: The mass values listed above for celestial bodies are based on current astronomical data and scientific estimates. While generally accurate, they may be rounded or subject to revision as new measurements become available.
Formula
The mass formula states that mass (m) is calculated as the product of an object’s density (ρ) and its volume (v). Mathematically, the formula for mass is expressed as m = ρ × v. This formula enables the calculation of the mass of an object based on its density and volume.
Practice problems
Problem #1
Calculate the mass of a steel object if the density of steel is 8050 kg/m3 and the volume of the object is 0.012 m3.
Solution
Given data:
- Mass of the object, m = ?
- Density of steel, ρ = 8050 kg/m3
- Volume of the object, v = 0.012 m3
Applying the formula:
- m = ρ × v
- m = 8050 × 0.012
- m = 96.6 kg
Therefore, the mass of a steel object is 96.6 kg.
Problem #2
If the density of a diamond is 3510 kg/m3 and the volume of the diamond is 0.005 m3, then calculate the mass of the diamond.
Solution
Given data:
- Density of a diamond, ρ = 3510 kg/m3
- Volume of a diamond, v = 0.005 m3
- Mass of a diamond, m = ?
Applying the formula:
- m = ρ × v
- m = 3510 × 0.005
- m = 17.55 kg
Therefore, the mass of a diamond is 17.55 kg.
Problem #3
The density of silver is 10497 kg/m3 and the volume of the silver object is 0.008 m3. Calculate the mass of the silver object.
Solution
Given data:
- Density of silver, ρ = 10497 kg/m3
- Volume of the object, v = 0.008 m3
- Mass of the object, m = ?
Applying the formula:
- m = ρ × v
- m = 10497 × 0.008
- m = 83.97 kg
Therefore, the mass of a silver is 83.97 kg.
Problem #4
Find the mass of a block of ice with a density of 917 kg/m3 and a volume of 0.007 m3.
Solution
Given data:
- Mass of ice block, m = ?
- Density of block, ρ = 917 kg/m3
- Volume of block, v = 0.007 m3
Applying the formula:
- m = ρ × v
- m = 917 × 0.007
- m = 6.41 kg
Therefore, the mass of an ice block is 6.41 kg.
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More topics
External links
- Examples of Mass – YourDictionary
- What is Mass? | Definition, Formula & Units – Study.com
- Mass in Math – Definition with Examples – SplashLearn
- Mass – Wikipedia
- What’s an example of mass? – Quora
- Examples of ‘mass’ in a sentence – Collins Dictionary
- Mass Definition & Meaning – Merriam-Webster
- Mass and Weight – Ducksters
- Mass Examples – SoftSchools.com
- How to Calculate Mass: 10 Steps (with Pictures) – wikiHow
- What Is Mass ⭐ Definition with Examples – Brighterly
- Mass, Weight, Density – HyperPhysics Concepts
- Mass Calculator – Calculator.net
Deep
Learnool.com was founded by Deep Rana, who is a mechanical engineer by profession and a blogger by passion. He has a good conceptual knowledge on different educational topics and he provides the same on this website. He loves to learn something new everyday and believes that the best utilization of free time is developing a new skill.