Iridium Bohr model

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In the iridium Bohr model, the nucleus holds 77 protons and 115 neutrons. Encircling this nucleus are six electron shells, carrying a total of 77 electrons.

To draw the iridium Bohr model, represent the 77 protons, 115 neutrons, and 77 electrons. Begin by sketching the nucleus, and then draw the six electron shells. The first five shells should contain 2, 8, 18, 32, and 15 electrons, respectively, while the sixth shell holds the remaining 2 electrons.

Steps

Find protons, neutrons, and electrons of iridium atom

Iridium has 77 protons, 115 neutrons, and 77 electrons.

Iridium protons

• Protons = atomic number

From the periodic table, find the atomic number of iridium.

The atomic number of iridium is 77. Hence, iridium has a total of 77 protons.

Iridium neutrons

• Neutrons = atomic mass – atomic number

The atomic mass of iridium is 192.217, so we’ll take the roundup value as 192. And the atomic number of iridium is 77.

Subtract the atomic number (77) from the atomic mass (192). Hence, iridium has a total of 192 – 77 = 115 neutrons.

Iridium electrons

• Electrons = atomic number

The atomic number of iridium is 77. Hence, iridium has a total of 77 electrons.

Draw nucleus of iridium atom

The nucleus of an iridium atom contains 77 protons and 115 neutrons. So draw the nucleus of iridium atom as follows:

Now in the next step, draw the 1^st electron shell and start marking electrons.

Draw 1^st electron shell

Remember that we have a total of 77 electrons.

The 1^st electron shell (containing s subshell) can hold up to a maximum of 2 electrons. So draw the 1^st electron shell as follows:

In the above image, 1 represents the 1^st electron shell that contains 1s subshell. And the green color represents the number of electrons in that subshell. This means that the 1^st electron shell has a total of 2 electrons.

Since we have already used 2 electrons in the 1^st electron shell, now we have 77 – 2 = 75 electrons left. So in the next step, we have to draw the 2^nd electron shell.

Draw 2^nd electron shell

The 2^nd electron shell (containing s subshell and p subshell) can hold up to a maximum of 8 electrons. So draw the 2^nd electron shell as follows:

In the above image, 2 represents the 2^nd electron shell that contains 2s and 2p subshells. And the green and orange color represents the number of electrons in that subshell. This means that the 2^nd electron shell has a total of 8 electrons.

Now we have already used 10 electrons in 1^st and 2^nd electron shells, so we have 77 – 10 = 67 electrons left. So in the next step, we have to draw the 3^rd electron shell.

Draw 3^rd electron shell

The 3^rd electron shell (containing s subshell, p subshell, and d subshell) can hold up to a maximum of 18 electrons. So draw the 3^rd electron shell as follows:

In the above image, 3 represents the 3^rd electron shell that contains 3s, 3p, and 3d subshells. And the green, orange, and pink color represents the number of electrons in that subshell. This means that the 3^rd electron shell has a total of 18 electrons.

Now we have already used 28 electrons in 1^st, 2^nd, and 3^rd electron shells, so we have 77 – 28 = 49 electrons left. So in the next step, we have to draw the 4^th electron shell.

Draw 4^th electron shell

The 4^th electron shell (containing s subshell, p subshell, d subshell, and f subshell) can hold up to a maximum of 32 electrons. So draw the 4^th electron shell as follows:

In the above image, 4 represents the 4^th electron shell that contains 4s, 4p, 4d, and 4f subshells. And the green, orange, pink, and blue color represents the number of electrons in that subshell. This means that the 4^th electron shell has a total of 32 electrons.

Now we have already used 60 electrons in 1^st, 2^nd, 3^rd, and 4^th electron shells, so we have 77 – 60 = 17 electrons left. So in the next step, we have to draw the 5^th electron shell.

Draw 5^th electron shell

The 5^th electron shell can hold up to a maximum of 50 electrons. So draw the 5^th electron shell as follows:

In the above image, 5 represents the 5^th electron shell that contains 5s, 5p, and 5d subshells. And the green, orange, and pink color represents the number of electrons in that subshell. This means that the 5^th electron shell has a total of 15 electrons.

The 5^th electron shell contains only 5s, 5p, and 5d subshells, and not a 5f subshell. This is because according to the aufbau principle, the 6s subshell is filled first and then 4f, 5d, 6p… and so on.

Now we have already used 75 electrons in 1^st, 2^nd, 3^rd, 4^th, and 5^th electron shells, so we have 77 – 75 = 2 electrons left. So in the next step, we have to draw the 6^th electron shell.

Draw 6^th electron shell

The 6^th electron shell can hold up to a maximum of 72 electrons. So draw the 6^th electron shell as follows:

In the above image, 6 represents the 6^th electron shell that contains 6s subshell. And the green color represents the number of electrons in that subshell. This means that the 6^th electron shell has a total of 2 electrons.

That’s it! This is the final Bohr model of iridium atom as we have used all 77 electrons: 2 electrons in the 1^st electron shell, 8 electrons in the 2^nd electron shell, 18 electrons in the 3^rd electron shell, 32 electrons in the 4^th electron shell, 15 electrons in the 5^th electron shell, and 2 electrons in the 6^th electron shell.

Next: Platinum Bohr model

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Related

• Iridium

More topics

• Iridium electron configuration
• Iridium orbital diagram

External links

• File:77 iridium (Ir) enhanced Bohr model.png – Wikimedia Commons
• Chemical Elements.com – Iridium (Ir) – Chemical Elements.com
• What is the Bohr model for Iridium? – Topblogtenz
• Iridium (Ir) – Periodic Table – ChemicalAid