**Acceleration **(a) is equal to the ratio of **change in velocity** (Δv) to the **time **(t). Using the formula of acceleration: **a = (v**_{f}** – v**_{i}**)/t**, the value of acceleration of an object can be calculated.

Let’s solve some problems based on this equation, so you’ll get a clear idea.

## Acceleration Practice Problems

**Problem 1:** One car is initially at rest. In 12 s, a car accelerates to 24 m/s. What is the acceleration of a car?

Solution:

Given data:

Time taken by a car, t = 12 s

Initial velocity of a car, v_{i} = 0 m/s

Final velocity of a car, v_{f} = 24 m/s

Acceleration of a car, a = ?

Using the formula of acceleration,

a = (v_{f} – v_{i})/t

a = (24 – 0)/12

a = 24/12

a = 2 m/s^{2}

Therefore, the acceleration of a car is **2 m/s ^{2}**.

**Problem 2:** An athlete accelerates from 5 m/s to 25 m/s in 5 s. Calculate the acceleration of an athlete.

Solution:

Given data:

Initial velocity of an athlete, v_{i} = 5 m/s

Final velocity of an athlete, v_{f} = 25 m/s

Time taken by an athlete, t = 5 s

Acceleration of an athlete, a = ?

Using the formula of acceleration,

a = (v_{f} – v_{i})/t

a = (25 – 5)/5

a = 20/5

a = 4 m/s^{2}

Therefore, the acceleration of an athlete is **4 m/s ^{2}**.

**Problem 3:** A bike accelerating at 35 m/s comes to rest in 7 s, when the brakes are applied to it. Calculate the deceleration of a bike.

Solution:

Given data:

Initial velocity of a bike, v_{i} = 35 m/s

Final velocity of a bike, v_{f} = 0 m/s

Time taken by a bike, t = 7 s

Deceleration of a bike, a = ?

Using the formula of acceleration,

a = (v_{f} – v_{i})/t

a = (0 – 35)/7

a = (-35)/7

a = -5 m/s^{2}

Therefore, the deceleration of a bike is **-5 m/s ^{2}**.

**Problem 4:** A truck accelerates from 12 m/s to 24 m/s in 4 s. What is the acceleration of a truck?

Solution:

Given data:

Initial velocity of a truck, v_{i} = 12 m/s

Final velocity of a truck, v_{f} = 24 m/s

Time taken by a truck, t = 4 s

Acceleration of a truck, a = ?

Using the formula of acceleration,

a = (v_{f} – v_{i})/t

a = (24 – 12)/4

a = 12/4

a = 3 m/s^{2}

Therefore, the acceleration of a truck is **3 m/s ^{2}**.

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**Related:**

- Free Fall Equation
- Air Resistance Formula
- Terminal Velocity Equation
- Gravity Equation
- Inertia Formula
- Momentum Equation
- Mass Formula
- Velocity Formula
- Pressure Equation
- Kinematic Equations
- Friction Equation

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