Arsenic Bohr model

In the arsenic Bohr model, the nucleus comprises 33 protons and 42 neutrons. Orbiting this nucleus are four electron shells, carrying a total of 33 electrons.

To draw the arsenic Bohr model, represent the 33 protons, 42 neutrons, and 33 electrons. Begin by sketching the nucleus, and then draw the four electron shells. The first three shells should contain 2, 8, and 18 electrons, respectively, while the fourth shell holds the remaining 5 electrons.

Contents

Steps

Write protons, neutrons, and electrons of arsenic atom

Arsenic has 33 protons, 42 neutrons, and 33 electrons.

Draw nucleus of arsenic atom

The nucleus of an arsenic atom contains 33 protons and 42 neutrons. So draw the nucleus of arsenic atom as follows:

Now in the next step, draw the 1st electron shell and start marking electrons.

Draw 1st electron shell

Remember that we have a total of 33 electrons.

The 1st electron shell (containing s subshell) can hold up to a maximum of 2 electrons. So draw the 1st electron shell as follows:

In the above image, 1 represents the 1st electron shell that contains 1s subshell. And the green color represents the number of electrons in that subshell. This means that the 1st electron shell has a total of 2 electrons.

Since we have already used 2 electrons in the 1st electron shell, now we have 33 – 2 = 31 electrons left. So in the next step, we have to draw the 2nd electron shell.

Draw 2nd electron shell

The 2nd electron shell (containing s subshell and p subshell) can hold up to a maximum of 8 electrons. So draw the 2nd electron shell as follows:

In the above image, 2 represents the 2nd electron shell that contains 2s and 2p subshells. And the green and orange color represents the number of electrons in that subshell. This means that the 2nd electron shell has a total of 8 electrons.

Now we have already used 10 electrons in 1st and 2nd electron shells, so we have 33 – 10 = 23 electrons left. So in the next step, we have to draw the 3rd electron shell.

Draw 3rd electron shell

The 3rd electron shell (containing s subshell, p subshell, and d subshell) can hold up to a maximum of 18 electrons. So draw the 3rd electron shell as follows:

In the above image, 3 represents the 3rd electron shell that contains 3s, 3p and 3d subshells. And the green, orange, and pink color represents the number of electrons in that subshell. This means that the 3rd electron shell has a total of 18 electrons.

Now we have already used 28 electrons in 1st, 2nd, and 3rd electron shells, so we have 33 – 28 = 5 electrons left. So in the next step, we have to draw the 4th electron shell.

Draw 4th electron shell

The 4th electron shell (containing s subshell, p subshell, d subshell, and f subshell) can hold up to a maximum of 32 electrons. So draw the 4th electron shell as follows:

In the above image, 4 represents the 4th electron shell that contains 4s and 4p subshells. And the green and orange color represents the number of electrons in that subshell. This means that the 4th electron shell has a total of 5 electrons.

Thatâ€™s it! This is the final Bohr model of arsenic atom as we have used all 33 electrons: 2 electrons in the 1st electron shell, 8 electrons in the 2nd electron shell, 18 electrons in the 3rd electron shell, and 5 electrons in the 4th electron shell.

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