Selenium Bohr model

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The Bohr model of selenium contains a nucleus having 34 protons and 45 neutrons in the center, and around this nucleus, there are four electron shells containing 34 electrons.

Contents

Steps

Here’s how you can draw the Bohr model of selenium step by step.

#1 Write protons, neutrons, and electrons of selenium atom
#2 Draw nucleus of selenium atom
#3 Draw 1^st electron shell
#4 Draw 2^nd electron shell
#5 Draw 3^rd electron shell
#6 Draw 4^th electron shell

Let’s break down each step in detail.

#1 Write protons, neutrons, and electrons of selenium atom

Selenium has 34 protons, 45 neutrons, and 34 electrons.

Learn how to find: Selenium protons neutrons electrons

#2 Draw nucleus of selenium atom

The nucleus of a selenium atom contains 34 protons and 45 neutrons. So draw the nucleus of selenium atom as follows:

Now in the next step, draw the 1^st electron shell and start marking electrons.

#3 Draw 1^st electron shell

Remember that we have a total of 34 electrons.

The 1^st electron shell (containing s subshell) can hold up to a maximum of 2 electrons. So draw the 1^st electron shell as follows:

Selenium shell 1 — Selenium 1^st electron shell drawn

In the above image, 1 represents the 1^st electron shell that contains 1s subshell. And the green color represents the number of electrons in that subshell. This means that the 1^st electron shell has a total of 2 electrons.

Since we have already used 2 electrons in the 1^st electron shell, now we have 34 – 2 = 32 electrons left. So in the next step, we have to draw the 2^nd electron shell.

#4 Draw 2^nd electron shell

The 2^nd electron shell (containing s subshell and p subshell) can hold up to a maximum of 8 electrons. So draw the 2^nd electron shell as follows:

Selenium shell 2 — Selenium 2^nd electron shell drawn

In the above image, 2 represents the 2^nd electron shell that contains 2s and 2p subshells. And the green and orange color represents the number of electrons in that subshell. This means that the 2^nd electron shell has a total of 8 electrons.

Now we have already used 10 electrons in 1^st and 2^nd electron shells, so we have 34 – 10 = 24 electrons left. So in the next step, we have to draw the 3^rd electron shell.

#5 Draw 3^rd electron shell

The 3^rd electron shell (containing s subshell, p subshell, and d subshell) can hold up to a maximum of 18 electrons. So draw the 3^rd electron shell as follows:

Selenium shell 3 — Selenium 3^rd electron shell drawn

In the above image, 3 represents the 3^rd electron shell that contains 3s, 3p and 3d subshells. And the green, orange, and pink color represents the number of electrons in that subshell. This means that the 3^rd electron shell has a total of 18 electrons.

Now we have already used 28 electrons in 1^st, 2^nd, and 3^rd electron shells, so we have 34 – 28 = 6 electrons left. So in the next step, we have to draw the 4^th electron shell.

#6 Draw 4^th electron shell

The 4^th electron shell (containing s subshell, p subshell, d subshell, and f subshell) can hold up to a maximum of 32 electrons. So draw the 4^th electron shell as follows:

Selenium shell 4 — Selenium 4^th electron shell drawn

In the above image, 4 represents the 4^th electron shell that contains 4s and 4p subshells. And the green and orange color represents the number of electrons in that subshell. This means that the 4^th electron shell has a total of 6 electrons.

That’s it! This is the final Bohr model of selenium atom as we have used all 34 electrons: 2 electrons in the 1^st electron shell, 8 electrons in the 2^nd electron shell, 18 electrons in the 3^rd electron shell, and 6 electrons in the 4^th electron shell.

Next: Bromine Bohr model

Selenium

Selenium Bohr model

Steps