
Charles law formula states that the volume (V) of a given quantity of gas directly depends upon its temperature (T), which means that the volume of the gas increases as its temperature increases. Here’s the formula of charles law: V1/T1 = V2/T2
Let’s solve some problems based on this formula, so you’ll get a clear idea.
Charles Law Practice Problems
Problem 1: A 2 L of hydrogen gas is filled in a rubber ball at a temperature of 10 °C. Calculate the final volume of the gas, if the temperature is increased to 90 °C.
Solution:
Given data:
Initial volume of the gas, V1 = 2 L
Initial temperature of the gas, T1 = 10 °C = 283 K
Final volume of the gas, V2 = ?
Final temperature of the gas, T2 = 90 °C = 363 K
Using the formula of charles law,
V1/T1 = V2/T2
V2 = (V1 × T2) ÷ T1
V2 = (2 × 363) ÷ 283
V2 = 726 ÷ 283
V2 = 2.56 L
Therefore, the final volume of the gas is 2.56 L.
Problem 2: A 3 L of helium gas is filled in a rubber ball and is heated at a temperature of 12 °C. If the volume of the gas changes to 4 L, then calculate the final temperature of the gas.
Solution:
Given data:
Initial volume of the gas, V1 = 3 L
Initial temperature of the gas, T1 = 12 °C = 285 K
Final temperature of the gas, T2 = ?
Final volume of the gas, V2 = 4 L
Using the formula of charles law,
V1/T1 = V2/T2
T2 = (V2 × T1) ÷ V1
T2 = (4 × 285) ÷ 3
T2 = 1140 ÷ 3
T2 = 380 K = 107 °C
Therefore, the final temperature of the gas is 107 °C.
Problem 3: One container is filled with a few liters of hydrogen gas and is heated to a temperature of 20 °C. If the final volume of the gas is 8 L and the final temperature of the gas is 50 °C, then what is the initial volume of the gas?
Solution:
Given data:
Initial temperature of the gas, T1 = 20 °C = 293 K
Final volume of the gas, V2 = 8 L
Final temperature of the gas, T2 = 50 °C = 323 K
Initial volume of the gas, V1 = ?
Using the formula of charles law,
V1/T1 = V2/T2
V1 = (V2 × T1) ÷ T2
V1 = (8 × 293) ÷ 323
V1 = 2344 ÷ 323
V1 = 7.25 L
Therefore, the initial volume of the gas is 7.25 L.
Problem 4: One box filled with 4 L of lithium gas is heated at an initial temperature. If the final temperature of the gas is 180 °C and the final volume of the gas is 6 L, then calculate the initial temperature of the gas.
Solution:
Given data:
Initial volume of the gas, V1 = 4 L
Final temperature of the gas, T2 = 180 °C = 453 K
Final volume of the gas, V2 = 6 L
Initial temperature of the gas, T1 = ?
Using the formula of charles law,
V1/T1 = V2/T2
T1 = (V1 × T2) ÷ V2
T1 = (4 × 453) ÷ 6
T1 = 1812 ÷ 6
T1 = 302 K = 29 °C
Therefore, the initial temperature of the gas is 29 °C.
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Related:
- Boyle’s Law Formula
- Gay Lussac’s Law Formula
- Avogadro’s Law Formula
- Ideal Gas Law Formula
- Dalton’s Law Formula
- Henry’s Law Equation
- Combined Gas Law Formula
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