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The **Charles’s law formula**, which is expressed as V_{1}/T_{1} = V_{2}/T_{2}, relates the volume and temperature of a gas. In this formula, V_{1} and T_{1} represent the initial volume and temperature of the gas, while V_{2} and T_{2} represent the final volume and temperature, respectively. This formula can be used to calculate the volume or temperature of a gas under different conditions, given the initial volume and temperature of the gas.

## Practice problems

### Problem #1

A rubber ball contains 2 L of hydrogen gas at an initial temperature of 10 ℃. Calculate the final volume of the gas if the temperature is increased to 90 ℃, according to Charles’s law.

**Solution**

Given data:

- Initial volume of the gas, V
_{1}= 2 L - Initial temperature of the gas, T
_{1}= 10 ℃ = 283 K - Final volume of the gas, V
_{2}= ? - Final temperature of the gas, T
_{2}= 90 ℃ = 363 K

Applying the formula:

- V
_{1}/T_{1}= V_{2}/T_{2} - V
_{2}= (V_{1}× T_{2}) ÷ T_{1} - V
_{2}= (2 × 363) ÷ 283 - V
_{2}= 726 ÷ 283 - V
_{2}= 2.56 L

Therefore, the final volume of the gas is **2.56 L**.

### Problem #2

A rubber ball is filled with 3 L of helium gas at a temperature of 12 ℃. If the volume of the gas changes to 4 L, what is the final temperature of the gas?

**Solution**

Given data:

- Initial volume of the gas, V
_{1}= 3 L - Initial temperature of the gas, T
_{1}= 12 ℃ = 285 K - Final volume of the gas, V
_{2}= 4 L - Final temperature of the gas, T
_{2}= ?

Applying the formula:

- V
_{1}/T_{1}= V_{2}/T_{2} - T
_{2}= (V_{2}× T_{1}) ÷ V_{1} - T
_{2}= (4 × 285) ÷ 3 - T
_{2}= 1140 ÷ 3 - T
_{2}= 380 K = 107 ℃

Therefore, the final temperature of the gas is **107 ℃**.

### Problem #3

A container is filled with a few liters of hydrogen gas at an initial temperature of 20 ℃. If the final volume of the gas is 8 L at a final temperature of 50 ℃, then what was the initial volume of the gas according to Charles’s law?

**Solution**

Given data:

- Initial temperature of the gas, T
_{1}= 20 ℃ = 293 K - Final volume of the gas, V
_{2}= 8 L - Final temperature of the gas, T
_{2}= 50 ℃ = 323 K - Initial volume of the gas, V
_{1}= ?

Applying the formula:

- V
_{1}/T_{1}= V_{2}/T_{2} - V
_{1}= (V_{2}× T_{1}) ÷ T_{2} - V
_{1}= (8 × 293) ÷ 323 - V
_{1}= 2344 ÷ 323 - V
_{1}= 7.25 L

Therefore, the initial volume of the gas is **7.25 L**.

### Problem #4

One box containing 4 L of argon gas is heated at an initial temperature. If the final temperature of the gas is 180 ℃ and the final volume of the gas is 6 L, then calculate the initial temperature of the gas.

**Solution**

Given data:

- Initial volume of the gas, V
_{1}= 4 L - Final temperature of the gas, T
_{2}= 180 ℃ = 453 K - Final volume of the gas, V
_{2}= 6 L - Initial temperature of the gas, T
_{1}= ?

Applying the formula:

- V
_{1}/T_{1}= V_{2}/T_{2} - T
_{1}= (V_{1}× T_{2}) ÷ V_{2} - T
_{1}= (4 × 453) ÷ 6 - T
_{1}= 1812 ÷ 6 - T
_{1}= 302 K = 29 ℃

Therefore, the initial temperature of the gas is **29 ℃**.

## Related

## More topics

- Boyle’s law formula
**Charles law formula**- Gay-Lussac’s law formula
- Avogadro’s law formula
- Ideal gas law formula
- Dalton’s law formula
- Henry’s law equation
- Combined gas law formula

## External links

- Charles’s Law — Overview & Formula – Expii
- Charles’ Law Calculator – Omni Calculator
- Charles’s law – Wikipedia
- Charles’ Law | Formula, Units & Application – Study.com
- Charles’s Law – Definition, Formula, Examples – Science Notes and Projects
- What Is the Formula for Charles’ Law? – ThoughtCo
- Charles Law – Kent’s Chemistry
- 6.3 Gas Laws – Boyle’s and Charles’ Laws – Chemistry LibreTexts
- Lesson Explainer: Charles’ Law Physics – Nagwa Limited
- Charles’s law | Definition & Facts – Britannica
- Charles’ Law | Understanding Gas Laws – ChemTalk
- Charles’ Law Formula – SoftSchools.com
- Charles’s Law Study Guide – Inspirit VR
- Charles law: Definition & Formula – Vaia
- Charles’ Law Calculator V1/T1=V2/T2 – SensorsONE
- Charle’s Law – Chemistry Steps
- Charles Law – Concept – Chemistry Video – Brightstorm
- Charles Law: Definition, Explanation, Formula and Equation – Science ABC
- Charles’ Law: Statement, Formula, Examples, and Graph – Chemistry Learner
- High School Chemistry : Using Charles’s Law – Varsity Tutors
- 3 Ways to Demonstrate Charles’s Law – wikiHow

Deep

Learnool.com was founded by Deep Rana, who is a mechanical engineer by profession and a blogger by passion. He has a good conceptual knowledge on different educational topics and he provides the same on this website. He loves to learn something new everyday and believes that the best utilization of free time is developing a new skill.