**Charles law formula** states that the **volume **(V) of a given quantity of gas directly depends upon its **temperature **(T), which means that the volume of the gas increases as its temperature increases. Here’s the formula of charles law: **V**_{1}**/T**_{1}** = V**_{2}**/T**_{2}

Let’s solve some problems based on this formula, so you’ll get a clear idea.

## Charles Law Practice Problems

**Problem 1:** A 2 L of hydrogen gas is filled in a rubber ball at a temperature of 10 °C. Calculate the final volume of the gas, if the temperature is increased to 90 °C.

Solution:

Given data:

Initial volume of the gas, V_{1} = 2 L

Initial temperature of the gas, T_{1} = 10 °C = 283 K

Final volume of the gas, V_{2} = ?

Final temperature of the gas, T_{2} = 90 °C = 363 K

Using the formula of charles law,

V_{1}/T_{1} = V_{2}/T_{2}

V_{2} = (V_{1} × T_{2}) ÷ T_{1}

V_{2} = (2 × 363) ÷ 283

V_{2} = 726 ÷ 283

V_{2} = 2.56 L

Therefore, the final volume of the gas is **2.56 L**.

**Problem 2:** A 3 L of helium gas is filled in a rubber ball and is heated at a temperature of 12 °C. If the volume of the gas changes to 4 L, then calculate the final temperature of the gas.

Solution:

Given data:

Initial volume of the gas, V_{1} = 3 L

Initial temperature of the gas, T_{1} = 12 °C = 285 K

Final temperature of the gas, T_{2} = ?

Final volume of the gas, V_{2} = 4 L

Using the formula of charles law,

V_{1}/T_{1} = V_{2}/T_{2}

T_{2} = (V_{2} × T_{1}) ÷ V_{1}

T_{2} = (4 × 285) ÷ 3

T_{2} = 1140 ÷ 3

T_{2} = 380 K = 107 °C

Therefore, the final temperature of the gas is **107 °C**.

**Problem 3:** One container is filled with a few liters of hydrogen gas and is heated to a temperature of 20 °C. If the final volume of the gas is 8 L and the final temperature of the gas is 50 °C, then what is the initial volume of the gas?

Solution:

Given data:

Initial temperature of the gas, T_{1} = 20 °C = 293 K

Final volume of the gas, V_{2} = 8 L

Final temperature of the gas, T_{2} = 50 °C = 323 K

Initial volume of the gas, V_{1} = ?

Using the formula of charles law,

V_{1}/T_{1} = V_{2}/T_{2}

V_{1} = (V_{2} × T_{1}) ÷ T_{2}

V_{1} = (8 × 293) ÷ 323

V_{1} = 2344 ÷ 323

V_{1} = 7.25 L

Therefore, the initial volume of the gas is **7.25 L**.

**Problem 4:** One box filled with 4 L of lithium gas is heated at an initial temperature. If the final temperature of the gas is 180 °C and the final volume of the gas is 6 L, then calculate the initial temperature of the gas.

Solution:

Given data:

Initial volume of the gas, V_{1} = 4 L

Final temperature of the gas, T_{2} = 180 °C = 453 K

Final volume of the gas, V_{2} = 6 L

Initial temperature of the gas, T_{1} = ?

Using the formula of charles law,

V_{1}/T_{1} = V_{2}/T_{2}

T_{1} = (V_{1} × T_{2}) ÷ V_{2}

T_{1} = (4 × 453) ÷ 6

T_{1} = 1812 ÷ 6

T_{1} = 302 K = 29 °C

Therefore, the initial temperature of the gas is **29 °C**.

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**Related:**

- Boyle’s Law Formula
- Gay Lussac’s Law Formula
- Avogadro’s Law Formula
- Ideal Gas Law Formula
- Dalton’s Law Formula
- Henry’s Law Equation
- Combined Gas Law Formula

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