**Boyle’s law formula** states that the **pressure **(P) of a given quantity of gas inversely depends upon its **volume **(V), which means that the pressure of the gas increases as its volume decreases. Here’s the formula of boyle’s law: **P**_{1}** V**_{1}** = P**_{2}** V**_{2}

Let’s solve some problems based on this formula, so you’ll get a clear idea.

## Boyle’s Law Practice Problems

**Problem 1:** A helium gas occupies the volume of 2 L at 5 atm pressure. Calculate the final volume of the gas, if the pressure of the gas is increased to 10 atm.

Solution:

Given data:

Initial volume of the gas, V_{1} = 2 L

Initial pressure of the gas, P_{1} = 5 atm

Final volume of the gas, V_{2} = ?

Final pressure of the gas, P_{2} = 10 atm

Using the formula of boyle’s law,

P_{1} V_{1} = P_{2} V_{2}

5 × 2 = 10 × V_{2}

V_{2} = 1 L

Therefore, the final volume of the gas is **1 L**.

**Problem 2:** A 3 L of helium gas is filled in a balloon at 12 atm pressure. If the volume of the gas increases to 6 L, then calculate the final pressure of the gas.

Solution:

Given data:

Initial volume of the gas, V_{1} = 3 L

Initial pressure of the gas, P_{1} = 12 atm

Final volume of the gas, V_{2} = 6 L

Final pressure of the gas, P_{2} = ?

Using the formula of boyle’s law,

P_{1} V_{1} = P_{2} V_{2}

12 × 3 = P_{2} × 6

P_{2} = 6 atm

Therefore, the final pressure of the gas is **6 atm**.

**Problem 3:** A large container is filled with a few liters of hydrogen gas at 2 atm pressure. When this hydrogen gas is released into a small container, it occupies the volume of 5 L at 8 atm pressure. Calculate the initial volume of the gas.

Solution:

Given data:

Initial pressure of the gas, P_{1} = 2 atm

Final volume of the gas, V_{2} = 5 L

Final pressure of the gas, P_{2} = 8 atm

Initial volume of the gas, V_{1} = ?

Using the formula of boyle’s law,

P_{1} V_{1} = P_{2} V_{2}

2 × V_{1} = 8 × 5

2 × V_{1} = 40

V_{1} = 20 L

Therefore, the initial volume of the gas is **20 L**.

**Problem 4:** A 12 L of argon gas filled in a large container exerts some pressure on the walls of a container. When this gas is released into a small container, it occupies the volume of 2 L at 6 atm pressure. Calculate the initial pressure of the gas.

Solution:

Given data:

Initial volume of the gas, V_{1} = 12 L

Final volume of the gas, V_{2} = 2 L

Final pressure of the gas, P_{2} = 6 atm

Initial pressure of the gas, P_{1} = ?

Using the formula of boyle’s law,

P_{1} V_{1} = P_{2} V_{2}

P_{1} × 12 = 6 × 2

P_{1} = 1 atm

Therefore, the initial pressure of the gas is **1 atm**.

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**Related:**

- Charles Law Formula
- Gay Lussac’s Law Formula
- Avogadro’s Law Formula
- Ideal Gas Law Formula
- Dalton’s Law Formula
- Henry’s Law Equation
- Combined Gas Law Formula

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