# Boyle’s Law Formula | Problems (With Answers)

Boyle’s law formula states that the pressure (P) of a given quantity of gas inversely depends upon its volume (V), which means that the pressure of the gas increases as its volume decreases. Here’s the formula of boyle’s law: P1 V1 = P2 V2

Let’s solve some problems based on this formula, so you’ll get a clear idea.

## Boyle’s Law Practice Problems

Problem 1: A helium gas occupies the volume of 2 L at 5 atm pressure. Calculate the final volume of the gas, if the pressure of the gas is increased to 10 atm.

Solution:

Given data:
Initial volume of the gas, V1 = 2 L
Initial pressure of the gas, P1 = 5 atm
Final volume of the gas, V2 = ?
Final pressure of the gas, P2 = 10 atm

Using the formula of boyle’s law,
P1 V1 = P2 V2
5 × 2 = 10 × V2
V2 = 1 L

Therefore, the final volume of the gas is 1 L.

Problem 2: A 3 L of helium gas is filled in a balloon at 12 atm pressure. If the volume of the gas increases to 6 L, then calculate the final pressure of the gas.

Solution:

Given data:
Initial volume of the gas, V1 = 3 L
Initial pressure of the gas, P1 = 12 atm
Final volume of the gas, V2 = 6 L
Final pressure of the gas, P2 = ?

Using the formula of boyle’s law,
P1 V1 = P2 V2
12 × 3 = P2 × 6
P2 = 6 atm

Therefore, the final pressure of the gas is 6 atm.

Problem 3: A large container is filled with a few liters of hydrogen gas at 2 atm pressure. When this hydrogen gas is released into a small container, it occupies the volume of 5 L at 8 atm pressure. Calculate the initial volume of the gas.

Solution:

Given data:
Initial pressure of the gas, P1 = 2 atm
Final volume of the gas, V2 = 5 L
Final pressure of the gas, P2 = 8 atm
Initial volume of the gas, V1 = ?

Using the formula of boyle’s law,
P1 V1 = P2 V2
2 × V1 = 8 × 5
2 × V1 = 40
V1 = 20 L

Therefore, the initial volume of the gas is 20 L.

Problem 4: A 12 L of argon gas filled in a large container exerts some pressure on the walls of a container. When this gas is released into a small container, it occupies the volume of 2 L at 6 atm pressure. Calculate the initial pressure of the gas.

Solution:

Given data:
Initial volume of the gas, V1 = 12 L
Final volume of the gas, V2 = 2 L
Final pressure of the gas, P2 = 6 atm
Initial pressure of the gas, P1 = ?

Using the formula of boyle’s law,
P1 V1 = P2 V2
P1 × 12 = 6 × 2
P1 = 1 atm

Therefore, the initial pressure of the gas is 1 atm.

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