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The **Boyle’s law formula**, which is succinctly expressed as P_{1} V_{1} = P_{2} V_{2}, describes the relationship between the pressure and volume of a given quantity of gas. In this formula, P_{1} and V_{1} represent the initial pressure and volume of the gas, while P_{2} and V_{2} represent the final pressure and volume, respectively. This formula is useful in calculating the pressure or volume of a gas under different conditions, given the initial pressure and volume of the gas.

## Practice problems

### Problem #1

A helium gas occupies a volume of 2 L at a pressure of 5 atm. Calculate the final volume of the gas if the pressure is increased to 10 atm.

**Solution**

Given data:

- Initial volume of the gas, V
_{1}= 2 L - Initial pressure of the gas, P
_{1}= 5 atm - Final volume of the gas, V
_{2}= ? - Final pressure of the gas, P
_{2}= 10 atm

Applying the formula:

- P
_{1}V_{1}= P_{2}V_{2} - 5 × 2 = 10 × V
_{2} - V
_{2}= 1 L

Therefore, the final volume of the gas is **1 L**.

### Problem #2

A balloon is filled with 3 L of helium gas at a pressure of 12 atm. If the volume of the gas increases to 6 L, calculate the final pressure of the gas.

**Solution**

Given data:

- Initial volume of the gas, V
_{1}= 3 L - Initial pressure of the gas, P
_{1}= 12 atm - Final volume of the gas, V
_{2}= 6 L - Final pressure of the gas, P
_{2}= ?

Applying the formula:

- P
_{1}V_{1}= P_{2}V_{2} - 12 × 3 = P
_{2}× 6 - P
_{2}= 6 atm

Therefore, the final pressure of the gas is **6 atm**.

### Problem #3

A large container initially contains a few liters of hydrogen gas at a pressure of 2 atm. When the gas is released into a small container, it occupies a volume of 5 L at a pressure of 8 atm. Calculate the initial volume of the gas.

**Solution**

Given data:

- Initial pressure of the gas, P
_{1}= 2 atm - Final volume of the gas, V
_{2}= 5 L - Final pressure of the gas, P
_{2}= 8 atm - Initial volume of the gas, V
_{1}= ?

Applying the formula:

- P
_{1}V_{1}= P_{2}V_{2} - 2 × V
_{1}= 8 × 5 - 2 × V
_{1}= 40 - V
_{1}= 20 L

Therefore, the initial volume of the gas is **20 L**.

### Problem #4

A container initially contains 12 L of argon gas at an unknown pressure. When released into a small container, the gas occupies a volume of 2 L at a pressure of 6 atm. Calculate the initial pressure of the gas.

**Solution**

Given data:

- Initial volume of the gas, V
_{1}= 12 L - Final volume of the gas, V
_{2}= 2 L - Final pressure of the gas, P
_{2}= 6 atm - Initial pressure of the gas, P
_{1}= ?

Applying the formula:

- P
_{1}V_{1}= P_{2}V_{2} - P
_{1}× 12 = 6 × 2 - P
_{1}= 1 atm

Therefore, the initial pressure of the gas is **1 atm**.

## Related

## More topics

**Boyle’s law formula**- Charles law formula
- Gay-Lussac’s law formula
- Avogadro’s law formula
- Ideal gas law formula
- Dalton’s law formula
- Henry’s law equation
- Combined gas law formula

## External links

- Boyle’s law | Definition, Equation, & Facts – Britannica
- Boyle’s law – Wikipedia
- Boyle’s Law Calculator – Omni Calculator
- 11.4: Boyle’s Law – Pressure and Volume – Chemistry LibreTexts
- Boyle’s Law — Overview & Formula – Expii
- Boyle’s Law | Understanding Gas Laws – ChemTalk
- The Formula for Boyle’s Law – ThoughtCo
- Solving Applications of Boyle’s Gas Law – Study.com
- Boyle’s Law, Charles’ Law, and Avogadro’s Law – Medium
- Lesson Explainer: Boyle’s Law – Nagwa Limited
- Boyle’s Law: Definition, Examples & Constant – Vaia
- Boyle’s Law Calculator P1V1=P2V2 – SensorsONE
- Boyle’s Law: Statement, Formula, Graph, and Examples – Chemistry Learner
- Boyle’s Law – Definition, Formula, Example – Science Notes and Projects
- Boyle’s Law Formula – SoftSchools.com
- Boyle’s Law Calculator – CalcTool

Deep

Learnool.com was founded by Deep Rana, who is a mechanical engineer by profession and a blogger by passion. He has a good conceptual knowledge on different educational topics and he provides the same on this website. He loves to learn something new everyday and believes that the best utilization of free time is developing a new skill.