
N2O4 (dinitrogen tetroxide) has two nitrogen atoms and four oxygen atoms.
In the N2O4 Lewis structure, there is a single bond between the two nitrogen atoms, and each nitrogen is attached with two oxygen atoms. The oxygen atom with single bonds has three lone pairs, and the oxygen atom with double bonds has two lone pairs.
Also, there is a negative (-1) charge on the two oxygen atoms with single bonds, and a positive (+1) charge on the two nitrogen atoms.
Alternative method: Lewis structure of N2O4
Rough sketch
- First, determine the total number of valence electrons

In the periodic table, nitrogen lies in group 15, and oxygen lies in group 16.
Hence, nitrogen has five valence electrons and oxygen has six valence electrons.
Since N2O4 has two nitrogen atoms and four oxygen atoms, so…
Valence electrons of two nitrogen atoms = 5 × 2 = 10
Valence electrons of four oxygen atoms = 6 × 4 = 24
And the total valence electrons = 10 + 24 = 34
Learn how to find: Nitrogen valence electrons and Oxygen valence electrons
- Second, find the total electron pairs
We have a total of 34 valence electrons. And when we divide this value by two, we get the value of total electron pairs.
Total electron pairs = total valence electrons ÷ 2
So the total electron pairs = 34 ÷ 2 = 17
- Third, determine the central atom
We have to place the least electronegative atom at the center.
Since nitrogen is less electronegative than oxygen, assume that the central atom is nitrogen.
Here, there are two nitrogen atoms, so we can assume any one as the central atom.
Let’s assume that the central atom is right nitrogen.
Therefore, place nitrogens in the center and oxygens on either side.
- And finally, draw the rough sketch

Lone pair
Here, we have a total of 17 electron pairs. And five bonds are already marked. So we have to only mark the remaining twelve electron pairs as lone pairs on the sketch.
Also remember that both (nitrogen and oxygen) are the period 2 elements, so they can not keep more than 8 electrons in their last shell.
Always start to mark the lone pairs from outside atoms. Here, the outside atoms are oxygens and left nitrogen.
So for each oxygen, there are three lone pairs, and for nitrogens, there is zero lone pair because all twelve electron pairs are over.
Mark the lone pairs on the sketch as follows:

Formal charge
Use the following formula to calculate the formal charges on atoms:
Formal charge = valence electrons – nonbonding electrons – ½ bonding electrons
For each nitrogen atom, formal charge = 5 – 0 – ½ (6) = +2
For each oxygen atom, formal charge = 6 – 6 – ½ (2) = -1
Here, both nitrogen and oxygen atoms have charges, so mark them on the sketch as follows:

The above structure is not a stable Lewis structure because both nitrogen and oxygen atoms have charges. Therefore, reduce the charges (as below) by converting lone pairs to bonds.
Convert a lone pair of the left oxygen atom to make a new N — O bond with the left nitrogen atom as follows:

Since there are charges on nitrogen and oxygen atoms, again convert a lone pair of the right oxygen atom to make a new N — O bond with the right nitrogen atom as follows:

Final structure
The final structure of N2O4 features two nitrogen atoms linked by a single covalent bond, with each nitrogen atom further connected to two oxygen atoms. In this arrangement, each nitrogen atom forms a double bond with one oxygen and a single bond with the other to satisfy the octet rule. Within this layout, the double-bonded oxygen atoms maintain two lone pairs each, while the single-bonded oxygen atoms retain three lone pairs, resulting in a formal charge of +1 on both nitrogen atoms and -1 on the two single-bonded oxygens. This configuration represents the most stable state for the molecule because the net charge remains zero and the octet rule is fulfilled for every atom. Consequently, this specific electronic distribution serves as the definitive and most accurate Lewis representation of dinitrogen tetroxide.
Next: SiS2 Lewis structure
External video
- N2O4 Lewis Structure: How to Draw the Lewis Structure for N2O4 – YouTube • Wayne Breslyn
External links
- https://www.chemistryscl.com/general/lewis-structure-of-N2O4/index.php
- https://techiescientist.com/n2o4-lewis-structure/
- https://www.thegeoexchange.org/chemistry/bonding/Lewis-Structures/N2O4-lewis-structure.html
- https://lambdageeks.com/n2o4-lewis-structure/
Deep
Learnool.com was founded by Deep Rana, who is a mechanical engineer by profession and a blogger by passion. He has a good conceptual knowledge on different educational topics and he provides the same on this website. He loves to learn something new everyday and believes that the best utilization of free time is developing a new skill.