**Pressure **(P) is equal to the ratio of **force** (F) to the **surface area **(A). Using the equation of pressure: **P = F/A**, the value of pressure acting on an object can be calculated.

Let’s solve some problems based on this equation, so you’ll get a clear idea.

## Pressure Practice Problems

**Problem 1:** Calculate the pressure acting on a disc of surface area 5 m^{2}, when a force of 50 N is exerted on it.

Solution:

Given data:

Pressure acting on a disc, P = ?

Surface area of a disc, A = 5 m^{2}

Force exerted on a disc, F = 50 N

Using the equation of pressure,

P = F/A

P = 50/5

P = 10 N/m^{2}

Therefore, the pressure acting on a disc is **10 N/m ^{2}**.

**Problem 2:** If a 10 N force is exerted on a box of surface area 2 m^{2}, then what is the value of pressure acting on a box?

Solution:

Given data:

Force exerted on a box, F = 10 N

Surface area of a box, A = 2 m^{2}

Pressure acting on a box, P = ?

Using the equation of pressure,

P = F/A

P = 10/2

P = 5 N/m^{2}

Therefore, the pressure acting on a box is **5 N/m ^{2}**.

**Problem 3:** A boy exerts a force of 28 N on the flat plate of surface area 4 m^{2}. Calculate the pressure acting on the flat plate.

Solution:

Given data:

Force exerted on the flat plate, F = 28 N

Surface area of the flat plate, A = 4 m^{2}

Pressure acting on the flat plate, P = ?

Using the equation of pressure,

P = F/A

P = 28/4

P = 7 N/m^{2}

Therefore, the pressure acting on the flat plate is **7 N/m ^{2}**.

**Problem 4:** A drummer exerts a force of 18 N on a drum head with the drumstick. If the surface area of a drum head is 3 m^{2}, then calculate the pressure acting on a drum head.

Solution:

Given data:

Force exerted on a drum head, F = 18 N

Surface area of a drum head, A = 3 m^{2}

Pressure acting on a drum head, P = ?

Using the equation of pressure,

P = F/A

P = 18/3

P = 6 N/m^{2}

Therefore, the pressure acting on a drum head is **6 N/m ^{2}**.

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