The orbital diagram of strontium shows that the 1s subshell has 2 electrons, the 2s subshell has 2 electrons, the 2p subshell has 6 electrons, the 3s subshell has 2 electrons, the 3p subshell has 6 electrons, the 4s subshell has 2 electrons, the 3d subshell has 10 electrons, the 4p subshell has 6 electrons, and the 5s subshell has 2 electrons.

## Steps

Here’s how you can draw the orbital diagram of strontium step by step.

Step #1: find electrons of strontium

Step #2: write electron configuration of strontium

Step #3: draw orbital diagram of strontium

Let’s break down each step in detail.

### #1 Find Electrons of Strontium

The atomic number of strontium represents the total number of electrons of strontium. Since the atomic number of strontium is 38, the total electrons of strontium are 38.

### #2 Write Electron Configuration of Strontium

The electron configuration of strontium is 1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 4s^{2} 3d^{10} 4p^{6} 5s^{2}.

Learn how to find: Strontium Electron Configuration

Now in the next step, start drawing the orbital diagram for strontium.

### #3 Draw Orbital Diagram of Strontium

Before drawing the orbital diagram, you should know the three general rules.

- Aufbau principle – electrons are first filled in lowest energy orbital and then in higher energy orbital
- Pauli exclusion principle – two electrons with the same spin can not occupy the same orbital
- Hund’s rule – each orbital should be first filled with one electron before being paired with a second electron

Also, you should know the number of orbitals in each subshell.

We can calculate the number of orbitals in each subshell using the formula: 2ℓ + 1

Where, ℓ = azimuthal quantum number of the subshell

For s subshell, ℓ = 0

For p subshell, ℓ = 1

For d subshell, ℓ = 2

For f subshell, ℓ = 3

So each s subshell has one orbital, each p subshell has three orbitals, each d subshell has five orbitals, and each f subshell has seven orbitals.

Now start to draw!

As mentioned above, the electron configuration of strontium is 1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 4s^{2} 3d^{10} 4p^{6} 5s^{2}. Hence, draw the blank orbital diagram of strontium up to 5s subshell as follows:

In the above orbital diagram, the box represents an orbital. Each orbital has a capacity of two electrons. And the arrows (↑↓) are drawn inside the box to represent electrons.

Now 1s^{2} indicates that the 1s subshell has 2 electrons. So draw two arrows in the 1s box showing two electrons as follows:

2s^{2} indicates that the 2s subshell has 2 electrons. So draw two arrows in the 2s box showing two electrons as follows:

2p^{6} indicates that the 2p subshell has 6 electrons. So draw six arrows in the 2p box showing six electrons as follows:

3s^{2} indicates that the 3s subshell has 2 electrons. So draw two arrows in the 3s box showing two electrons as follows:

3p^{6} indicates that the 3p subshell has 6 electrons. So draw six arrows in the 3p box showing six electrons as follows:

4s^{2} indicates that the 4s subshell has 2 electrons. So draw two arrows in the 4s box showing two electrons as follows:

3d^{10} indicates that the 3d subshell has 10 electrons. So draw ten arrows in the 3d box showing ten electrons as follows:

4p^{6} indicates that the 4p subshell has 6 electrons. So draw six arrows in the 4p box showing six electrons as follows:

5s^{2} indicates that the 5s subshell has 2 electrons. So draw two arrows in the 5s box showing two electrons as follows:

That’s it! This is the final orbital diagram of strontium as we have used all 38 electrons.

**Next:** Barium Orbital Diagram

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