Rubidium Bohr model

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In the rubidium Bohr model, the nucleus holds 37 protons and 48 neutrons. Orbiting this nucleus are five electron shells, carrying a total of 37 electrons.

To draw the rubidium Bohr model, outline the 37 protons, 48 neutrons, and 37 electrons. Begin by illustrating the nucleus, and then depict the five electron shells. The first four shells should contain 2, 8, 18, and 8 electrons, respectively, while the fifth shell holds the remaining electron.

Steps

Find protons, neutrons, and electrons of rubidium atom

Rubidium has 37 protons, 48 neutrons, and 37 electrons.

Rubidium protons

• Protons = atomic number

From the periodic table, find the atomic number of rubidium.

The atomic number of rubidium is 37. Hence, rubidium has a total of 37 protons.

Rubidium neutrons

• Neutrons = atomic mass – atomic number

The atomic mass of rubidium is 85.4678, so we’ll take the roundup value as 85. And the atomic number of rubidium is 37.

Subtract the atomic number (37) from the atomic mass (85). Hence, rubidium has a total of 85 – 37 = 48 neutrons.

Rubidium electrons

• Electrons = atomic number

The atomic number of rubidium is 37. Hence, rubidium has a total of 37 electrons.

Draw nucleus of rubidium atom

The nucleus of a rubidium atom contains 37 protons and 48 neutrons. So draw the nucleus of rubidium atom as follows:

Now in the next step, draw the 1^st electron shell and start marking electrons.

Draw 1^st electron shell

Remember that we have a total of 37 electrons.

The 1^st electron shell (containing s subshell) can hold up to a maximum of 2 electrons. So draw the 1^st electron shell as follows:

In the above image, 1 represents the 1^st electron shell that contains 1s subshell. And the green color represents the number of electrons in that subshell. This means that the 1^st electron shell has a total of 2 electrons.

Since we have already used 2 electrons in the 1^st electron shell, now we have 37 – 2 = 35 electrons left. So in the next step, we have to draw the 2^nd electron shell.

Draw 2^nd electron shell

The 2^nd electron shell (containing s subshell and p subshell) can hold up to a maximum of 8 electrons. So draw the 2^nd electron shell as follows:

In the above image, 2 represents the 2^nd electron shell that contains 2s and 2p subshells. And the green and orange color represents the number of electrons in that subshell. This means that the 2^nd electron shell has a total of 8 electrons.

Now we have already used 10 electrons in 1^st and 2^nd electron shells, so we have 37 – 10 = 27 electrons left. So in the next step, we have to draw the 3^rd electron shell.

Draw 3^rd electron shell

The 3^rd electron shell (containing s subshell, p subshell, and d subshell) can hold up to a maximum of 18 electrons. So draw the 3^rd electron shell as follows:

In the above image, 3 represents the 3^rd electron shell that contains 3s, 3p, and 3d subshells. And the green, orange, and pink color represents the number of electrons in that subshell. This means that the 3^rd electron shell has a total of 18 electrons.

Now we have already used 28 electrons in 1^st, 2^nd, and 3^rd electron shells, so we have 37 – 28 = 9 electrons left. So in the next step, we have to draw the 4^th electron shell.

Draw 4^th electron shell

The 4^th electron shell (containing s subshell, p subshell, d subshell, and f subshell) can hold up to a maximum of 32 electrons. So draw the 4^th electron shell as follows:

In the above image, 4 represents the 4^th electron shell that contains 4s and 4p subshells. And the green and orange color represents the number of electrons in that subshell. This means that the 4^th electron shell has a total of 8 electrons.

The 4^th electron shell contains only 4s and 4p subshells, and not 4d and 4f subshells. This is because according to the aufbau principle, the 5s subshell is filled first and then 4d, 5p, 6s… and so on.

Now we have already used 36 electrons in 1^st, 2^nd, 3^rd, and 4^th electron shells, so we have 37 – 36 = 1 electron left. So in the next step, we have to draw the 5^th electron shell.

Draw 5^th electron shell

The 5^th electron shell can hold up to a maximum of 50 electrons. So draw the 5^th electron shell as follows:

In the above image, 5 represents the 5^th electron shell that contains 5s subshell. And the green color represents the number of electrons in that subshell. This means that the 5^th electron shell has a total of 1 electron.

That’s it! This is the final Bohr model of rubidium atom as we have used all 37 electrons: 2 electrons in the 1^st electron shell, 8 electrons in the 2^nd electron shell, 18 electrons in the 3^rd electron shell, 8 electrons in the 4^th electron shell, and 1 electron in the 5^th electron shell.

Next: Strontium Bohr model

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Related

• Rubidium

More topics

• Rubidium orbital diagram
• Rubidium valence electrons

External links

• File:37 rubidium (Rb) enhanced Bohr model.png – Wikimedia Commons
• What is the Bohr model for Rubidium? – Chemistry QnA – Topblogtenz
• Chemical Elements.com – Rubidium (Rb) – Chemical Elements.com
• Bohr Diagrams of Atoms and Ions – Chemistry LibreTexts
• Rubidium (Rb) – Periodic Table – ChemicalAid