# Rubidium Bohr Model

The bohr model of rubidium contains a nucleus having 37 protons and 48 neutrons in the center, and around this nucleus, there are five electron shells containing 37 electrons.

## Steps

Here’s how you can draw the bohr model of rubidium step by step.

Step #1: find protons, neutrons, and electrons of rubidium atom
Step #2: draw nucleus of rubidium atom
Step #3: draw 1st electron shell
Step #4: draw 2nd electron shell
Step #5: draw 3rd electron shell
Step #6: draw 4th electron shell
Step #7: draw 5th electron shell

Let’s break down each step in detail.

### #1 Find Protons, Neutrons, and Electrons of Rubidium Atom

Rubidium has 37 protons, 48 neutrons, and 37 electrons.

#### Rubidium Protons

• Protons = atomic number

From the periodic table, find the atomic number of rubidium.

The atomic number of rubidium is 37. Hence, rubidium has a total of 37 protons.

#### Rubidium Neutrons

• Neutrons = atomic mass – atomic number

The atomic mass of rubidium is 85.4678, so we’ll take the roundup value as 85. And the atomic number of rubidium is 37.

Subtract the atomic number (37) from the atomic mass (85). Hence, rubidium has a total of 85 – 37 = 48 neutrons.

#### Rubidium Electrons

• Electrons = atomic number

The atomic number of rubidium is 37. Hence, rubidium has a total of 37 electrons.

### #2 Draw Nucleus of Rubidium Atom

The nucleus of a rubidium atom contains 37 protons and 48 neutrons. So draw the nucleus of rubidium atom as follows:

Now in the next step, draw the 1st electron shell and start marking electrons.

### #3 Draw 1st Electron Shell

Remember that we have a total of 37 electrons.

The 1st electron shell (containing s subshell) can hold up to a maximum of 2 electrons. So draw the 1st electron shell as follows:

In the above image, 1 represents the 1st electron shell that contains 1s subshell. And the green color represents the number of electrons in that subshell. This means that the 1st electron shell has a total of 2 electrons.

Since we have already used 2 electrons in the 1st electron shell, now we have 37 – 2 = 35 electrons left. So in the next step, we have to draw the 2nd electron shell.

### #4 Draw 2nd Electron Shell

The 2nd electron shell (containing s subshell and p subshell) can hold up to a maximum of 8 electrons. So draw the 2nd electron shell as follows:

In the above image, 2 represents the 2nd electron shell that contains 2s and 2p subshells. And the green and orange color represents the number of electrons in that subshell. This means that the 2nd electron shell has a total of 8 electrons.

Now we have already used 10 electrons in 1st and 2nd electron shells, so we have 37 – 10 = 27 electrons left. So in the next step, we have to draw the 3rd electron shell.

### #5 Draw 3rd Electron Shell

The 3rd electron shell (containing s subshell, p subshell, and d subshell) can hold up to a maximum of 18 electrons. So draw the 3rd electron shell as follows:

In the above image, 3 represents the 3rd electron shell that contains 3s, 3p, and 3d subshells. And the green, orange, and pink color represents the number of electrons in that subshell. This means that the 3rd electron shell has a total of 18 electrons.

Now we have already used 28 electrons in 1st, 2nd, and 3rd electron shells, so we have 37 – 28 = 9 electrons left. So in the next step, we have to draw the 4th electron shell.

### #6 Draw 4th Electron Shell

The 4th electron shell (containing s subshell, p subshell, d subshell, and f subshell) can hold up to a maximum of 32 electrons. So draw the 4th electron shell as follows:

In the above image, 4 represents the 4th electron shell that contains 4s and 4p subshells. And the green and orange color represents the number of electrons in that subshell. This means that the 4th electron shell has a total of 8 electrons.

The 4th electron shell contains only 4s and 4p subshells, and not 4d and 4f subshells. This is because according to the aufbau principle, the 5s subshell is filled first and then 4d, 5p, 6s… and so on.

Now we have already used 36 electrons in 1st, 2nd, 3rd, and 4th electron shells, so we have 37 – 36 = 1 electron left. So in the next step, we have to draw the 5th electron shell.

### #7 Draw 5th Electron Shell

The 5th electron shell can hold up to a maximum of 50 electrons. So draw the 5th electron shell as follows:

In the above image, 5 represents the 5th electron shell that contains 5s subshell. And the green color represents the number of electrons in that subshell. This means that the 5th electron shell has a total of 1 electron.

That’s it! This is the final bohr model of rubidium atom as we have used all 37 electrons: 2 electrons in the 1st electron shell, 8 electrons in the 2nd electron shell, 18 electrons in the 3rd electron shell, 8 electrons in the 4th electron shell, and 1 electron in the 5th electron shell.

Next: Strontium Bohr Model

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