# Antimony Bohr model

The information on this page is ✔ fact-checked.

In the antimony Bohr model, the nucleus comprises 51 protons and 71 neutrons. Surrounding this nucleus are five electron shells, accommodating a total of 51 electrons.

To draw the antimony Bohr model, represent the 51 protons, 71 neutrons, and 51 electrons. Begin by sketching the nucleus, and then draw the five electron shells. The first four shells should contain 2, 8, 18, and 18 electrons, respectively, while the fifth shell holds the remaining 5 electrons.

Contents

## Steps

### Find protons, neutrons, and electrons of antimony atom

Antimony has 51 protons, 71 neutrons, and 51 electrons.

#### Antimony protons

• Protons = atomic number

From the periodic table, find the atomic number of antimony.

The atomic number of antimony is 51. Hence, antimony has a total of 51 protons.

#### Antimony neutrons

• Neutrons = atomic mass – atomic number

The atomic mass of antimony is 121.76, so we’ll take the roundup value as 122. And the atomic number of antimony is 51.

Subtract the atomic number (51) from the atomic mass (122). Hence, antimony has a total of 122 – 51 = 71 neutrons.

#### Antimony electrons

• Electrons = atomic number

The atomic number of antimony is 51. Hence, antimony has a total of 51 electrons.

### Draw nucleus of antimony atom

The nucleus of an antimony atom contains 51 protons and 71 neutrons. So draw the nucleus of antimony atom as follows:

Now in the next step, draw the 1st electron shell and start marking electrons.

### Draw 1st electron shell

Remember that we have a total of 51 electrons.

The 1st electron shell (containing s subshell) can hold up to a maximum of 2 electrons. So draw the 1st electron shell as follows:

In the above image, 1 represents the 1st electron shell that contains 1s subshell. And the green color represents the number of electrons in that subshell. This means that the 1st electron shell has a total of 2 electrons.

Since we have already used 2 electrons in the 1st electron shell, now we have 51 – 2 = 49 electrons left. So in the next step, we have to draw the 2nd electron shell.

### Draw 2nd electron shell

The 2nd electron shell (containing s subshell and p subshell) can hold up to a maximum of 8 electrons. So draw the 2nd electron shell as follows:

In the above image, 2 represents the 2nd electron shell that contains 2s and 2p subshells. And the green and orange color represents the number of electrons in that subshell. This means that the 2nd electron shell has a total of 8 electrons.

Now we have already used 10 electrons in 1st and 2nd electron shells, so we have 51 – 10 = 41 electrons left. So in the next step, we have to draw the 3rd electron shell.

### Draw 3rd electron shell

The 3rd electron shell (containing s subshell, p subshell, and d subshell) can hold up to a maximum of 18 electrons. So draw the 3rd electron shell as follows:

In the above image, 3 represents the 3rd electron shell that contains 3s, 3p, and 3d subshells. And the green, orange, and pink color represents the number of electrons in that subshell. This means that the 3rd electron shell has a total of 18 electrons.

Now we have already used 28 electrons in 1st, 2nd, and 3rd electron shells, so we have 51 – 28 = 23 electrons left. So in the next step, we have to draw the 4th electron shell.

### Draw 4th electron shell

The 4th electron shell (containing s subshell, p subshell, d subshell, and f subshell) can hold up to a maximum of 32 electrons. So draw the 4th electron shell as follows:

In the above image, 4 represents the 4th electron shell that contains 4s, 4p, and 4d subshells. And the green, orange, and pink color represents the number of electrons in that subshell. This means that the 4th electron shell has a total of 18 electrons.

The 4th electron shell contains only 4s, 4p, and 4d subshells, and not a 4f subshell. This is because according to the aufbau principle, the 5s subshell is filled first and then 4d, 5p, 6s… and so on.

Now we have already used 46 electrons in 1st, 2nd, 3rd, and 4th electron shells, so we have 51 – 46 = 5 electrons left. So in the next step, we have to draw the 5th electron shell.

### Draw 5th electron shell

The 5th electron shell can hold up to a maximum of 50 electrons. So draw the 5th electron shell as follows:

In the above image, 5 represents the 5th electron shell that contains 5s and 5p subshells. And the green and orange color represents the number of electrons in that subshell. This means that the 5th electron shell has a total of 5 electrons.

That’s it! This is the final Bohr model of antimony atom as we have used all 51 electrons: 2 electrons in the 1st electron shell, 8 electrons in the 2nd electron shell, 18 electrons in the 3rd electron shell, 18 electrons in the 4th electron shell, and 5 electrons in the 5th electron shell.

Next: Tellurium Bohr model