Astatine Bohr model

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Astatine Bohr model
Astatine Bohr model | Image: Learnool

The astatine Bohr model has a nucleus with 85 protons and 125 neutrons. Orbiting this nucleus are six electron shells, holding a total of 85 electrons.

To draw the astatine Bohr model, outline the 85 protons, 125 neutrons, and 85 electrons. Start by illustrating the nucleus, and then draw the six electron shells. The first five shells should contain 2, 8, 18, 32, and 18 electrons, respectively, while the sixth shell holds the remaining 7 electrons.

Steps

Find protons, neutrons, and electrons of astatine atom

Astatine has 85 protons, 125 neutrons, and 85 electrons.

Astatine protons

  • Protons = atomic number

From the periodic table, find the atomic number of astatine.

Astatine location on periodic table | Image: Learnool

The atomic number of astatine is 85. Hence, astatine has a total of 85 protons.

Astatine neutrons

  • Neutrons = atomic mass – atomic number
Astatine neutrons
Astatine neutrons | Image: Learnool

The atomic mass of astatine is 210 and the atomic number of astatine is 85.

Subtract the atomic number (85) from the atomic mass (210). Hence, astatine has a total of 210 – 85 = 125 neutrons.

Astatine electrons

  • Electrons = atomic number
Astatine electrons
Astatine electrons | Image: Learnool

The atomic number of astatine is 85. Hence, astatine has a total of 85 electrons.

Draw nucleus of astatine atom

The nucleus of an astatine atom contains 85 protons and 125 neutrons. So draw the nucleus of astatine atom as follows:

Astatine nucleus
Astatine nucleus | Image: Learnool

Now in the next step, draw the 1st electron shell and start marking electrons.

Draw 1st electron shell

Remember that we have a total of 85 electrons.

The 1st electron shell (containing s subshell) can hold up to a maximum of 2 electrons. So draw the 1st electron shell as follows:

Astatine shell 1
Astatine 1st electron shell drawn | Image: Learnool

In the above image, 1 represents the 1st electron shell that contains 1s subshell. And the green color represents the number of electrons in that subshell. This means that the 1st electron shell has a total of 2 electrons.

Since we have already used 2 electrons in the 1st electron shell, now we have 85 – 2 = 83 electrons left. So in the next step, we have to draw the 2nd electron shell.

Draw 2nd electron shell

The 2nd electron shell (containing s subshell and p subshell) can hold up to a maximum of 8 electrons. So draw the 2nd electron shell as follows:

Astatine shell 2
Astatine 2nd electron shell drawn | Image: Learnool

In the above image, 2 represents the 2nd electron shell that contains 2s and 2p subshells. And the green and orange color represents the number of electrons in that subshell. This means that the 2nd electron shell has a total of 8 electrons.

Now we have already used 10 electrons in 1st and 2nd electron shells, so we have 85 – 10 = 75 electrons left. So in the next step, we have to draw the 3rd electron shell.

Draw 3rd electron shell

The 3rd electron shell (containing s subshell, p subshell, and d subshell) can hold up to a maximum of 18 electrons. So draw the 3rd electron shell as follows:

Astatine shell 3
Astatine 3rd electron shell drawn | Image: Learnool

In the above image, 3 represents the 3rd electron shell that contains 3s, 3p, and 3d subshells. And the green, orange, and pink color represents the number of electrons in that subshell. This means that the 3rd electron shell has a total of 18 electrons.

Now we have already used 28 electrons in 1st, 2nd, and 3rd electron shells, so we have 85 – 28 = 57 electrons left. So in the next step, we have to draw the 4th electron shell.

Draw 4th electron shell

The 4th electron shell (containing s subshell, p subshell, d subshell, and f subshell) can hold up to a maximum of 32 electrons. So draw the 4th electron shell as follows:

Astatine shell 4
Astatine 4th electron shell drawn | Image: Learnool

In the above image, 4 represents the 4th electron shell that contains 4s, 4p, 4d, and 4f subshells. And the green, orange, pink, and blue color represents the number of electrons in that subshell. This means that the 4th electron shell has a total of 32 electrons.

Now we have already used 60 electrons in 1st, 2nd, 3rd, and 4th electron shells, so we have 85 – 60 = 25 electrons left. So in the next step, we have to draw the 5th electron shell.

Draw 5th electron shell

The 5th electron shell can hold up to a maximum of 50 electrons. So draw the 5th electron shell as follows:

Astatine shell 5
Astatine 5th electron shell drawn | Image: Learnool

In the above image, 5 represents the 5th electron shell that contains 5s, 5p, and 5d subshells. And the green, orange, and pink color represents the number of electrons in that subshell. This means that the 5th electron shell has a total of 18 electrons.

The 5th electron shell contains only 5s, 5p, and 5d subshells, and not a 5f subshell. This is because according to the aufbau principle, the 6s subshell is filled first and then 4f, 5d, 6p… and so on.

Now we have already used 78 electrons in 1st, 2nd, 3rd, 4th, and 5th electron shells, so we have 85 – 78 = 7 electrons left. So in the next step, we have to draw the 6th electron shell.

Draw 6th electron shell

The 6th electron shell can hold up to a maximum of 72 electrons. So draw the 6th electron shell as follows:

Astatine shell 6
Astatine 6th electron shell drawn | Image: Learnool

In the above image, 6 represents the 6th electron shell that contains 6s and 6p subshells. And the green and orange color represents the number of electrons in that subshell. This means that the 6th electron shell has a total of 7 electrons.

That’s it! This is the final Bohr model of astatine atom as we have used all 85 electrons: 2 electrons in the 1st electron shell, 8 electrons in the 2nd electron shell, 18 electrons in the 3rd electron shell, 32 electrons in the 4th electron shell, 18 electrons in the 5th electron shell, and 7 electrons in the 6th electron shell.

Next: Radon Bohr model

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Learnool.com was founded by Deep Rana, who is a mechanical engineer by profession and a blogger by passion. He has a good conceptual knowledge on different educational topics and he provides the same on this website. He loves to learn something new everyday and believes that the best utilization of free time is developing a new skill.

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