Bismuth Bohr model

The information on this page is ✔ fact-checked.

In the bismuth Bohr model, the nucleus comprises 83 protons and 126 neutrons. Surrounding this nucleus are six electron shells, accommodating a total of 83 electrons.

To draw the bismuth Bohr model, represent the 83 protons, 126 neutrons, and 83 electrons. Begin by sketching the nucleus, and then draw the six electron shells. The first five shells should contain 2, 8, 18, 32, and 18 electrons, respectively, while the sixth shell holds the remaining 5 electrons.

Steps

Write protons, neutrons, and electrons of bismuth atom

Bismuth has 83 protons, 126 neutrons, and 83 electrons.

Learn how to find: Bismuth protons neutrons electrons

Draw nucleus of bismuth atom

The nucleus of a bismuth atom contains 83 protons and 126 neutrons. So draw the nucleus of bismuth atom as follows:

Now in the next step, draw the 1^st electron shell and start marking electrons.

Draw 1^st electron shell

Remember that we have a total of 83 electrons.

The 1^st electron shell (containing s subshell) can hold up to a maximum of 2 electrons. So draw the 1^st electron shell as follows:

In the above image, 1 represents the 1^st electron shell that contains 1s subshell. And the green color represents the number of electrons in that subshell. This means that the 1^st electron shell has a total of 2 electrons.

Since we have already used 2 electrons in the 1^st electron shell, now we have 83 – 2 = 81 electrons left. So in the next step, we have to draw the 2^nd electron shell.

Draw 2^nd electron shell

The 2^nd electron shell (containing s subshell and p subshell) can hold up to a maximum of 8 electrons. So draw the 2^nd electron shell as follows:

In the above image, 2 represents the 2^nd electron shell that contains 2s and 2p subshells. And the green and orange color represents the number of electrons in that subshell. This means that the 2^nd electron shell has a total of 8 electrons.

Now we have already used 10 electrons in 1^st and 2^nd electron shells, so we have 83 – 10 = 73 electrons left. So in the next step, we have to draw the 3^rd electron shell.

Draw 3^rd electron shell

The 3^rd electron shell (containing s subshell, p subshell, and d subshell) can hold up to a maximum of 18 electrons. So draw the 3^rd electron shell as follows:

In the above image, 3 represents the 3^rd electron shell that contains 3s, 3p, and 3d subshells. And the green, orange, and pink color represents the number of electrons in that subshell. This means that the 3^rd electron shell has a total of 18 electrons.

Now we have already used 28 electrons in 1^st, 2^nd, and 3^rd electron shells, so we have 83 – 28 = 55 electrons left. So in the next step, we have to draw the 4^th electron shell.

Draw 4^th electron shell

The 4^th electron shell (containing s subshell, p subshell, d subshell, and f subshell) can hold up to a maximum of 32 electrons. So draw the 4^th electron shell as follows:

In the above image, 4 represents the 4^th electron shell that contains 4s, 4p, 4d, and 4f subshells. And the green, orange, pink, and blue color represents the number of electrons in that subshell. This means that the 4^th electron shell has a total of 32 electrons.

Now we have already used 60 electrons in 1^st, 2^nd, 3^rd, and 4^th electron shells, so we have 83 – 60 = 23 electrons left. So in the next step, we have to draw the 5^th electron shell.

Draw 5^th electron shell

The 5^th electron shell can hold up to a maximum of 50 electrons. So draw the 5^th electron shell as follows:

In the above image, 5 represents the 5^th electron shell that contains 5s, 5p, and 5d subshells. And the green, orange, and pink color represents the number of electrons in that subshell. This means that the 5^th electron shell has a total of 18 electrons.

The 5^th electron shell contains only 5s, 5p, and 5d subshells, and not a 5f subshell. This is because according to the aufbau principle, the 6s subshell is filled first and then 4f, 5d, 6p… and so on.

Now we have already used 78 electrons in 1^st, 2^nd, 3^rd, 4^th, and 5^th electron shells, so we have 83 – 78 = 5 electrons left. So in the next step, we have to draw the 6^th electron shell.

Draw 6^th electron shell

The 6^th electron shell can hold up to a maximum of 72 electrons. So draw the 6^th electron shell as follows:

In the above image, 6 represents the 6^th electron shell that contains 6s and 6p subshells. And the green and orange color represents the number of electrons in that subshell. This means that the 6^th electron shell has a total of 5 electrons.

That’s it! This is the final Bohr model of thallium atom as we have used all 81 electrons: 2 electrons in the 1^st electron shell, 8 electrons in the 2^nd electron shell, 18 electrons in the 3^rd electron shell, 32 electrons in the 4^th electron shell, 18 electrons in the 5^th electron shell, and 5 electrons in the 6^th electron shell.

Next: Astatine Bohr model

📝 Your feedback matters. Visit our contact page.

Related

• Bismuth

More topics

• Bismuth electron configuration
• Bismuth orbital diagram
• Bismuth protons neutrons electrons
• Bismuth valence electrons

External links

• File:83 bismuth (Bi) ehnanced Bohr model.png – Wikimedia Commons
• Chemical Elements.com – Bismuth (Bi) – Chemical Elements.com
• Bismuth (Bi) – Periodic Table – ChemicalAid
• What is the Bohr model for Bismuth? – Topblogtenz