# Chromium Bohr model

The Bohr model of chromium contains a nucleus having 24 protons and 28 neutrons in the center, and around this nucleus, there are four electron shells containing 24 electrons.

Contents

## Steps

Here’s how you can draw the Bohr model of chromium step by step.

#1 Write protons, neutrons, and electrons of chromium atom
#2 Draw nucleus of chromium atom
#3 Draw 1st electron shell
#4 Draw 2nd electron shell
#5 Draw 3rd electron shell
#6 Draw 4th electron shell

Let’s break down each step in detail.

### #1 Write protons, neutrons, and electrons of chromium atom

Chromium has 24 protons, 28 neutrons, and 24 electrons.

### #2 Draw nucleus of chromium atom

The nucleus of a chromium atom contains 24 protons and 28 neutrons. So draw the nucleus of chromium atom as follows:

Now in the next step, draw the 1st electron shell and start marking electrons.

### #3 Draw 1st electron shell

Remember that we have a total of 24 electrons.

The 1st electron shell (containing s subshell) can hold up to a maximum of 2 electrons. So draw the 1st electron shell as follows:

In the above image, 1 represents the 1st electron shell that contains 1s subshell. And the green color represents the number of electrons in that subshell. This means that the 1st electron shell has a total of 2 electrons.

Since we have already used 2 electrons in the 1st electron shell, now we have 24 – 2 = 22 electrons left. So in the next step, we have to draw the 2nd electron shell.

### #4 Draw 2nd electron shell

The 2nd electron shell (containing s subshell and p subshell) can hold up to a maximum of 8 electrons. So draw the 2nd electron shell as follows:

In the above image, 2 represents the 2nd electron shell that contains 2s and 2p subshells. And the green and orange color represents the number of electrons in that subshell. This means that the 2nd electron shell has a total of 8 electrons.

Now we have already used 10 electrons in 1st and 2nd electron shells, so we have 24 – 10 = 14 electrons left. So in the next step, we have to draw the 3rd electron shell.

### #5 Draw 3rd electron shell

The 3rd electron shell (containing s subshell, p subshell, and d subshell) can hold up to a maximum of 18 electrons. So draw the 3rd electron shell as follows:

In the above image, 3 represents the 3rd electron shell that contains 3s, 3p, and 3d subshells. And the green, orange, and pink color represents the number of electrons in that subshell. This means that the 3rd electron shell has a total of 13 electrons.

In the 3rd electron shell, the 3d subshell has only five electrons. This is because according to the aufbau principle, the 4s subshell is filled first and then 3d, 4p, 5s… and so on.

Now we have already used 23 electrons in 1st, 2nd, and 3rd electron shells, so we have 24 – 23 = 1 electrons left. So in the next step, we have to draw the 4th electron shell.

Note: A half-full 3d subshell is more stable than a partially filled 3d subshell. That’s why the 3d subshell has five electrons (instead of four electrons). And the 4s subshell has one electron (instead of two electrons).

For a detailed explanation, check the orbital diagram of chromium.

### #6 Draw 4th electron shell

The 4th electron shell (containing s subshell, p subshell, d subshell, and f subshell) can hold up to a maximum of 32 electrons. So draw the 4th electron shell as follows:

In the above image, 4 represents the 4th electron shell that contains 4s subshell. And the green color represents the number of electrons in that subshell. This means that the 4th electron shell has a total of 1 electron.

That’s it! This is the final Bohr model of chromium atom as we have used all 24 electrons: 2 electrons in the 1st electron shell, 8 electrons in the 2nd electron shell, 13 electrons in the 3rd electron shell, and 1 electron in the 4th electron shell.

Next: Manganese Bohr model