Henry’s law equation states that the concentration (C) of a dissolved gas in a given quantity of liquid directly depends upon the partial pressure (P) of that gas, which means that the concentration of a dissolved gas increases as the partial pressure of the gas increases. Here’s the equation of henry’s law: C = k P
Let’s solve some problems based on this equation, so you’ll get a clear idea.
Henry’s Law Practice Problems
Problem 1: Calculate the concentration of a helium gas dissolved in water, if the partial pressure of the gas is 4 atm and the value of henry’s law constant, k = 15 L atm/mol.
Solution:
Given data:
Concentration of a dissolved gas, C = ?
Partial pressure of the gas, P = 4 atm
Henry’s law constant, k = 15 L atm/mol
Using the equation of henry’s law,
C = k P
C = 15 × 4
C = 60 mol/L
Therefore, the concentration of a helium gas dissolved in water is 60 mol/L.
Problem 2: A 14 mol/L concentration of a hydrogen gas is dissolved in a liquid bottle. Calculate the partial pressure of the gas, if the value of henry’s constant, k = 7 L atm/mol.
Solution:
Given data:
Concentration of a dissolved gas, C = 14 mol/L
Partial pressure of the gas, P = ?
Henry’s law constant, k = 7 L atm/mol
Using the equation of henry’s law,
C = k P
14 = 7 × P
P = 2 atm
Therefore, the partial pressure of the gas is 2 atm.
Problem 3: What is the concentration of an argon gas dissolved in water, which is having a 6 atm partial pressure? (Take the value of henry’s law constant, k = 25 L atm/mol)
Solution:
Given data:
Concentration of a dissolved gas, C = ?
Partial pressure of the gas, P = 6 atm
Henry’s law constant, k = 25 L atm/mol
Using the equation of henry’s law,
C = k P
C = 25 × 6
C = 150 mol/L
Therefore, the concentration of an argon gas dissolved in water is 150 mol/L.
Problem 4: Calculate the partial pressure of a lithium gas dissolved in water. If the concentration of a lithium gas is 20 mol/L and the value of henry’s law constant, k = 5 L atm/mol.
Solution:
Given data:
Partial pressure of the gas, P = ?
Concentration of a dissolved gas, C = 20 mol/L
Henry’s law constant, k = 5 L atm/mol
Using the equation of henry’s law,
C = k P
20 = 5 × P
P = 4 atm
Therefore, the partial pressure of the gas is 4 atm.
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