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**Henry’s law equation**, represented by C = k P, describes the relationship between the concentration of a dissolved gas (C) in a given quantity of liquid and the partial pressure (P) of that gas. In this equation, k is a constant known as Henry’s law constant, which is specific to each gas-liquid system.

## Practice problems

### Problem #1

Calculate the concentration of oxygen gas dissolved in water, given that the partial pressure of the gas is 4 atm and the Henry’s law constant, k = 15 L atm/mol.

**Solution**

Given data:

- Concentration of a dissolved gas, C = ?
- Partial pressure of the gas, P = 4 atm
- Henry’s law constant, k = 15 L atm/mol

Applying the formula:

- C = k P
- C = 15 × 4
- C = 60 mol/L

Therefore, the concentration of a helium gas dissolved in water is **60 mol/L**.

### Problem #2

A liquid bottle contains a hydrogen gas concentration of 14 mol/L. Calculate the partial pressure of the gas, if the Henry’s law constant, k = 7 L atm/mol.

**Solution**

Given data:

- Concentration of a dissolved gas, C = 14 mol/L
- Partial pressure of the gas, P = ?
- Henry’s law constant, k = 7 L atm/mol

Applying the formula:

- C = k P
- 14 = 7 × P
- P = 2 atm

Therefore, the partial pressure of the gas is **2 atm**.

### Problem #3

If the partial pressure of argon gas in water is 6 atm and the Henry’s law constant is 25 L atm/mol, what is the concentration of argon gas dissolved in water?

**Solution**

Given data:

- Partial pressure of the gas, P = 6 atm
- Henry’s law constant, k = 25 L atm/mol
- Concentration of a dissolved gas, C = ?

Applying the formula:

- C = k P
- C = 25 × 6
- C = 150 mol/L

Therefore, the concentration of an argon gas dissolved in water is **150 mol/L**.

### Problem #4

Calculate the partial pressure of a hydrogen gas dissolved in water, given a concentration of 20 mol/L and the Henry’s law constant, k = 5 L atm/mol.

**Solution**

Given data:

- Partial pressure of the gas, P = ?
- Concentration of a dissolved gas, C = 20 mol/L
- Henry’s law constant, k = 5 L atm/mol

Applying the formula:

- C = k P
- 20 = 5 × P
- P = 4 atm

Therefore, the partial pressure of the gas is **4 atm**.

## Related

- Boyle’s law formula
- Charles law formula
- Gay-Lussac’s law formula
- Avogadro’s law formula
- Ideal gas law formula
- Dalton’s law formula
**Henry’s law equation**- Combined gas law formula

## External links

- Henry’s Law – Chemistry LibreTexts
- Henry’s law – Wikipedia
- Henry’s Law | Overview, Equation & Limitations – Study.com
- Henry’s Law – Kent’s Chemistry
- Henry’s Law – an overview – ScienceDirect
- Henry’s Law Example Problem – ThoughtCo
- Henry’s Law – ChemTalk
- Henry’s Law Constant Calculator – Calculator Academy
- Henry’s Law Calculations Video Tutorial & Practice – Pearson
- Henry’s Law for Gas Solubility Chemistry Tutorial – AUS-e-TUTE
- Henry’s Law: Statement, Constant, and Equation – Chemistry Learner
- Henry’s law equation(Henry’s law) Formula – SoftSchools.com
- What Is Henry’s Law? – Science ABC

Deep

Learnool.com was founded by Deep Rana, who is a mechanical engineer by profession and a blogger by passion. He has a good conceptual knowledge on different educational topics and he provides the same on this website. He loves to learn something new everyday and believes that the best utilization of free time is developing a new skill.