**Henry’s law equation** states that the **concentration** (C) of a dissolved gas in a given quantity of liquid directly depends upon the **partial pressure** (P) of that gas, which means that the concentration of a dissolved gas increases as the partial pressure of the gas increases. Here’s the equation of henry’s law: **C = k P**

Let’s solve some problems based on this equation, so you’ll get a clear idea.

## Henry’s Law Practice Problems

**Problem 1:** Calculate the concentration of a helium gas dissolved in water, if the partial pressure of the gas is 4 atm and the value of henry’s law constant, k = 15 L atm/mol.

Solution:

Given data:

Concentration of a dissolved gas, C = ?

Partial pressure of the gas, P = 4 atm

Henry’s law constant, k = 15 L atm/mol

Using the equation of henry’s law,

C = k P

C = 15 × 4

C = 60 mol/L

Therefore, the concentration of a helium gas dissolved in water is **60 mol/L**.

**Problem 2:** A 14 mol/L concentration of a hydrogen gas is dissolved in a liquid bottle. Calculate the partial pressure of the gas, if the value of henry’s constant, k = 7 L atm/mol.

Solution:

Given data:

Concentration of a dissolved gas, C = 14 mol/L

Partial pressure of the gas, P = ?

Henry’s law constant, k = 7 L atm/mol

Using the equation of henry’s law,

C = k P

14 = 7 × P

P = 2 atm

Therefore, the partial pressure of the gas is **2 atm**.

**Problem 3:** What is the concentration of an argon gas dissolved in water, which is having a 6 atm partial pressure? (Take the value of henry’s law constant, k = 25 L atm/mol)

Solution:

Given data:

Concentration of a dissolved gas, C = ?

Partial pressure of the gas, P = 6 atm

Henry’s law constant, k = 25 L atm/mol

Using the equation of henry’s law,

C = k P

C = 25 × 6

C = 150 mol/L

Therefore, the concentration of an argon gas dissolved in water is **150 mol/L**.

**Problem 4:** Calculate the partial pressure of a lithium gas dissolved in water. If the concentration of a lithium gas is 20 mol/L and the value of henry’s law constant, k = 5 L atm/mol.

Solution:

Given data:

Partial pressure of the gas, P = ?

Concentration of a dissolved gas, C = 20 mol/L

Henry’s law constant, k = 5 L atm/mol

Using the equation of henry’s law,

C = k P

20 = 5 × P

P = 4 atm

Therefore, the partial pressure of the gas is **4 atm**.

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