N2F2 Lewis Structure

N2F2 Lewis Structure

N2F2 (dinitrogen difluoride) has two nitrogen atoms and two fluorine atoms. In the lewis structure of N2F2, there is a double bond between the two nitrogen atoms, and each nitrogen is attached with one fluorine atom. Each fluorine atom has three lone pairs, and each nitrogen atom has one lone pair.

Steps

Here’s how you can draw the N2F2 lewis structure step by step.

Step #1: draw sketch
Step #2: mark lone pairs
Step #3: mark charges
Step #4: minimize charges
Step #5: minimize charges again (if there are)

Let’s break down each step in detail.

#1 Draw Sketch

  • First, determine the total number of valence electrons

In the periodic table, nitrogen lies in group 15, and fluorine lies in group 17.

Hence, nitrogen has five valence electrons and fluorine has seven valence electrons.

Since N2F2 has two nitrogen atoms and two fluorine atoms, so…

Valence electrons of two nitrogen atoms = 5 × 2 = 10
Valence electrons of two fluorine atoms = 7 × 2 = 14

And the total valence electrons = 10 + 14 = 24

  • Second, find the total electron pairs

We have a total of 24 valence electrons. And when we divide this value by two, we get the value of total electron pairs.

Total electron pairs = total valence electrons ÷ 2

So the total electron pairs = 24 ÷ 2 = 12

  • Third, determine the central atom

We have to place the least electronegative atom at the center.

Since nitrogen is less electronegative than fluorine, assume that the central atom is nitrogen.

Here, there are two nitrogen atoms, so we can assume any one as the central atom.

Let’s assume that the central atom is left nitrogen.

Therefore, place nitrogens in the center and fluorines on either side.

  • And finally, draw the rough sketch
N2F2 Lewis Structure (Step 1)

#2 Mark Lone Pairs

Here, we have a total of 12 electron pairs. And three bonds are already marked. So we have to only mark the remaining nine electron pairs as lone pairs on the sketch.

Also remember that both (nitrogen and fluorine) are the period 2 elements, so they can not keep more than 8 electrons in their last shell.

Always start to mark the lone pairs from outside atoms. Here, the outside atoms are fluorines and right nitrogen.

So for each fluorine, there are three lone pairs, for right nitrogen, there are two lone pairs, and for left nitrogen, there is one lone pair.

Mark the lone pairs on the sketch as follows:

N2F2 Lewis Structure (Step 2)

#3 Mark Charges

Use the following formula to calculate the formal charges on atoms:

Formal charge = valence electrons – nonbonding electrons – ½ bonding electrons

For left nitrogen atom, formal charge = 5 – 2 – ½ (4) = +1

For right nitrogen atom, formal charge = 5 – 4 – ½ (4) = +1

For each fluorine atom, formal charge = 7 – 6 – ½ (2) = 0

Here, both nitrogen atoms have charges, so mark them on the sketch as follows:

N2F2 Lewis Structure (Step 3)

The above structure is not a stable lewis structure because both nitrogen atoms have charges. Therefore, reduce the charges (as below) by converting lone pairs to bonds.

#4 Minimize Charges

Convert a lone pair of the right nitrogen atom to make a new C — C bond with the left nitrogen atom as follows:

N2F2 Lewis Structure (Step 4)

In the above structure, you can see that the central atom (left nitrogen) forms an octet. Hence, the octet rule is satisfied.

Also, the above structure is more stable than the previous structures. Therefore, this structure is the stable lewis structure of N2F2.

Next: N2O5 Lewis Structure

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