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**Newton’s law of universal gravitation formula**, F_{G} = G [m_{1} m_{2}] ÷ r^{2}, describes the gravitational force (F_{G}) between two objects. In this formula, G represents the gravitational constant, m_{1} and m_{2} denote the masses of the objects, and r signifies the distance between them. This equation enables the calculation of the gravitational force exerted between objects based on their masses and the distance separating them.

## Practice problems

### Problem #1

Calculate the gravitational force between a wooden crate weighing 8 kg and a car weighing 100 kg. The distance between the centers of the wooden crate and the car is 200 m. Take the value of the universal gravitational constant, G, as 6.67 × 10^{-11} N m^{2}/kg^{2}.

**Solution**

Given data:

- Gravitational force between a wooden crate and a car, F
_{G}= ? - Mass of a wooden crate, m
_{1}= 8 kg - Mass of a car, m
_{2}= 100 kg - Distance between the centers of a wooden crate and a car, r = 200 m
- Universal gravitational constant, G = 6.67 × 10
^{-11}N m^{2}/kg^{2}

Applying the formula:

- F
_{G}= G [m_{1}m_{2}] ÷ r^{2} - F
_{G}= (6.67 × 10^{-11}× 8 × 100) ÷ (200)^{2} - F
_{G}= (6.67 × 10^{-11}× 8 × 200) ÷ (4 × 10^{4}) - F
_{G}= (2668 × 10^{-11}) ÷ 10^{4} - F
_{G}= 26.68 × 10^{-13}N

Therefore, the gravitational force between a wooden crate and a car is **26.68 × 10 ^{-13} N**.

### Problem #2

Determine the gravitational force between two spheres with masses of 4 kg and 10 kg, separated by a distance of 500 m. Take the value of the universal gravitational constant, G, as 6.67 × 10^{-11} N m^{2}/kg^{2}.

**Solution**

Given data:

- Gravitational force between the two spheres, F
_{G}= ? - Mass of the sphere 1, m
_{1}= 4 kg - Mass of the sphere 2, m
_{2}= 10 kg - Distance between the two spheres, r = 500 m
- Universal gravitational constant, G = 6.67 × 10
^{-11}N m^{2}/kg^{2}

Applying the formula:

- F
_{G}= G [m_{1}m_{2}] ÷ r^{2} - F
_{G}= (6.67 × 10^{-11}× 4 × 10) ÷ (500)^{2} - F
_{G}= (6.67 × 10^{-11}× 4 × 10) ÷ (25 × 10^{4}) - F
_{G}= (1.06 × 10^{-11}) ÷ 10^{3} - F
_{G}= 1.06 × 10^{-14}N

Therefore, the gravitational force between the two spheres is **1.06 × 10 ^{-14} N**.

### Problem #3

Two satellites, one with a mass of 5000 kg and the other with a mass of 4000 kg, are floating in space. If the distance between them is 2500 m, calculate the gravitational force acting between them. Take the value of the universal gravitational constant, G, as 6.67 × 10^{-11} N m^{2}/kg^{2}.

**Solution**

Given data:

- Mass of a satellite 1, m
_{1}= 5000 kg - Mass of a satellite 2, m
_{2}= 4000 kg - Distance between the centers of the two satellites, r = 2500 m
- Gravitational force between the two satellites, F
_{G}= ? - Universal gravitational constant, G = 6.67 × 10
^{-11}N m^{2}/kg^{2}

Applying the formula:

- F
_{G}= G [m_{1}m_{2}] ÷ r^{2} - F
_{G}= (6.67 × 10^{-11}× 5000 × 4000) ÷ (2500)^{2} - F
_{G}= (6.67 × 10^{-11}× 20 × 10^{6}) ÷ (625 × 10^{4}) - F
_{G}= (0.2134 × 10^{-5}) ÷ 10^{4} - F
_{G}= 0.2134 × 10^{-9}N - F
_{G}= 21.34 × 10^{-11}N

Therefore, the gravitational force between the two satellites is **21.34 × 10 ^{-11} N**.

### Problem #4

Determine the gravitational force between two asteroids with masses of m_{1} = 4 × 10^{15} kg and m_{2} = 8 × 10^{14} kg, located at a distance of 10^{10} m from each other. Take the value of the universal gravitational constant, G, as 6.67 × 10^{-11} N m^{2}/kg^{2}.

**Solution**

Given data:

- Gravitational force between the two asteroids, F
_{G}= ? - Mass of the asteroid 1, m
_{1}= 4 × 10^{15}kg - Mass of the asteroid 2, m
_{2}= 8 × 10^{14}kg - Distance between the two asteroids, r = 10
^{10}m - Universal gravitational constant, G = 6.67 × 10
^{-11}N m^{2}/kg^{2}

Applying the formula:

- F
_{G}= G [m_{1}m_{2}] ÷ r^{2} - F
_{G}= (6.67 × 10^{-11}× 4 × 10^{15}× 8 × 10^{14}) ÷ (10^{10})^{2} - F
_{G}= (213.44 × 10^{18}) ÷ 10^{20} - F
_{G}= 213.44 × 10^{-2} - F
_{G}= 2.13 N

Therefore, the gravitational force between the two asteroids is **2.13 N**.

## Related

- Newton’s second law equation
**Newton’s law of universal gravitation formula**- Newton’s law of cooling equation
- Coulomb’s law equation
- Snell’s law equation
- Ohm’s law equation
- Hooke’s law equation

## External links

- https://www.physicsclassroom.com/class/circles/Lesson-3/Newton-s-Law-of-Universal-Gravitation
- http://www.atmo.arizona.edu/students/courselinks/fall12/atmo170a1s1/lecture_notes/mass_weight_density_pressure/univ_grav.html
- https://study.com/academy/lesson/the-law-of-universal-gravitation-definition-importance-examples.html
- https://www.studysmarter.us/explanations/math/mechanics-maths/newtons-law-of-gravitation/
- https://www.omnicalculator.com/physics/gravitational-force

Deep

Learnool.com was founded by Deep Rana, who is a mechanical engineer by profession and a blogger by passion. He has a good conceptual knowledge on different educational topics and he provides the same on this website. He loves to learn something new everyday and believes that the best utilization of free time is developing a new skill.