Rutherfordium Bohr model

The Bohr model of rutherfordium contains a nucleus having 104 protons and 157 neutrons in the center, and around this nucleus, there are seven electron shells containing 104 electrons.

Contents

Steps

Here’s how you can draw the Bohr model of rutherfordium step by step.

#1 Find protons, neutrons, and electrons of rutherfordium atom
#2 Draw nucleus of rutherfordium atom
#3 Draw 1st electron shell
#4 Draw 2nd electron shell
#5 Draw 3rd electron shell
#6 Draw 4th electron shell
#7 Draw 5th electron shell
#8 Draw 6th electron shell
#9 Draw 7th electron shell

Let’s break down each step in detail.

#1 Find protons, neutrons, and electrons of rutherfordium atom

Rutherfordium has 104  protons, 157 neutrons, and 104 electrons.

Rutherfordium protons

• Protons = atomic number

From the periodic table, find the atomic number of rutherfordium.

The atomic number of rutherfordium is 104. Hence, rutherfordium has a total of 104 protons.

Rutherfordium neutrons

• Neutrons = atomic mass – atomic number

The atomic mass of rutherfordium is 261 and the atomic number of rutherfordium is 104.

Subtract the atomic number (104) from the atomic mass (261). Hence, rutherfordium has a total of 261 – 104 = 157 neutrons.

Rutherfordium electrons

• Electrons = atomic number

The atomic number of rutherfordium is 104. Hence, rutherfordium has a total of 104 electrons.

#2 Draw nucleus of rutherfordium atom

The nucleus of a rutherfordium atom contains 104 protons and 157 neutrons. So draw the nucleus of rutherfordium atom as follows:

Now in the next step, draw the 1st electron shell and start marking electrons.

#3 Draw 1st electron shell

Remember that we have a total of 104 electrons.

The 1st electron shell (containing s subshell) can hold up to a maximum of 2 electrons. So draw the 1st electron shell as follows:

In the above image, 1 represents the 1st electron shell that contains 1s subshell. And the green color represents the number of electrons in that subshell. This means that the 1st electron shell has a total of 2 electrons.

Since we have already used 2 electrons in the 1st electron shell, now we have 104 – 2 = 102 electrons left. So in the next step, we have to draw the 2nd electron shell.

#4 Draw 2nd electron shell

The 2nd electron shell (containing s subshell and p subshell) can hold up to a maximum of 8 electrons. So draw the 2nd electron shell as follows:

In the above image, 2 represents the 2nd electron shell that contains 2s and 2p subshells. And the green and orange color represents the number of electrons in that subshell. This means that the 2nd electron shell has a total of 8 electrons.

Now we have already used 10 electrons in 1st and 2nd electron shells, so we have 104 – 10 = 94 electrons left. So in the next step, we have to draw the 3rd electron shell.

#5 Draw 3rd electron shell

The 3rd electron shell (containing s subshell, p subshell, and d subshell) can hold up to a maximum of 18 electrons. So draw the 3rd electron shell as follows:

In the above image, 3 represents the 3rd electron shell that contains 3s, 3p, and 3d subshells. And the green, orange, and pink color represents the number of electrons in that subshell. This means that the 3rd electron shell has a total of 18 electrons.

Now we have already used 28 electrons in 1st, 2nd, and 3rd electron shells, so we have 104 – 28 = 76 electrons left. So in the next step, we have to draw the 4th electron shell.

#6 Draw 4th Electron shell

The 4th electron shell (containing s subshell, p subshell, d subshell, and f subshell) can hold up to a maximum of 32 electrons. So draw the 4th electron shell as follows:

In the above image, 4 represents the 4th electron shell that contains 4s, 4p, 4d, and 4f subshells. And the green, orange, pink, and blue color represents the number of electrons in that subshell. This means that the 4th electron shell has a total of 32 electrons.

Now we have already used 60 electrons in 1st, 2nd, 3rd, and 4th electron shells, so we have 104 – 60 = 44 electrons left. So in the next step, we have to draw the 5th electron shell.

#7 Draw 5th electron shell

The 5th electron shell can hold up to a maximum of 50 electrons. So draw the 5th electron shell as follows:

In the above image, 5 represents the 5th electron shell that contains 5s, 5p, 5d, and 5f subshells. And the green, orange, pink, and blue color represents the number of electrons in that subshell. This means that the 5th electron shell has a total of 32 electrons.

Now we have already used 92 electrons in 1st, 2nd, 3rd, 4th, and 5th electron shells, so we have 104 – 92 = 12 electrons left. So in the next step, we have to draw the 6th electron shell.

#8 Draw 6th electron shell

The 6th electron shell can hold up to a maximum of 72 electrons. So draw the 6th electron shell as follows:

In the above image, 6 represents the 6th electron shell that contains 6s, 6p, and 6d subshells. And the green, orange, and pink color represents the number of electrons in that subshell. This means that the 6th electron shell has a total of 10 electrons.

In the 6th electron shell, the 6d subshell has only two electrons. This is because according to the aufbau principle, the 7s subshell is filled first and then 5f, 6d, 7p… and so on.

Now we have already used 102 electrons in 1st, 2nd, 3rd, 4th, 5th, and 6th electron shells, so we have 104 – 102 = 2 electrons left. So in the next step, we have to draw the 7th electron shell.

#9 Draw 7th electron shell

The 7th electron shell can hold up to a maximum of 98 electrons. So draw the 7th electron shell as follows:

In the above image, 7 represents the 7th electron shell that contains 7s subshell. And the green color represents the number of electrons in that subshell. This means that the 7th electron shell has a total of 2 electrons.

That’s it! This is the final Bohr model of rutherfordium atom as we have used all 104 electrons: 2 electrons in the 1st electron shell, 8 electrons in the 2nd electron shell, 18 electrons in the 3rd electron shell, 32 electrons in the 4th electron shell, 32 electrons in the 5th electron shell, 10 electrons in the 6th electron shell, and 2 electrons in the 7th electron shell.