# Copernicium Bohr model

The copernicium Bohr model illustrates a nucleus with 112 protons and 173 neutrons. Orbiting this nucleus are seven electron shells, housing a total of 112 electrons.

To draw the copernicium Bohr model, represent the 112 protons, 173 neutrons, and 112 electrons. Begin by sketching the nucleus, and then draw the seven electron shells. The first six shells should contain 2, 8, 18, 32, 32, and 18 electrons, respectively, while the seventh shell holds the remaining 2 electrons.

Contents

## Steps

### Find protons, neutrons, and electrons of copernicium atom

Copernicium has 112  protons, 173 neutrons, and 112 electrons.

#### Copernicium protons

• Protons = atomic number

From the periodic table, find the atomic number of copernicium.

The atomic number of copernicium is 112. Hence, copernicium has a total of 112 protons.

#### Copernicium neutrons

• Neutrons = atomic mass – atomic number

The atomic mass of copernicium is 285 and the atomic number of copernicium is 112.

Subtract the atomic number (112) from the atomic mass (285). Hence, copernicium has a total of 285 – 112 = 173 neutrons.

#### Copernicium electrons

• Electrons = atomic number

The atomic number of copernicium is 112. Hence, copernicium has a total of 112 electrons.

### Draw nucleus of copernicium atom

The nucleus of a copernicium atom contains 112 protons and 173 neutrons. So draw the nucleus of copernicium atom as follows:

Now in the next step, draw the 1st electron shell and start marking electrons.

### Draw 1st electron shell

Remember that we have a total of 112 electrons.

The 1st electron shell (containing s subshell) can hold up to a maximum of 2 electrons. So draw the 1st electron shell as follows:

In the above image, 1 represents the 1st electron shell that contains 1s subshell. And the green color represents the number of electrons in that subshell. This means that the 1st electron shell has a total of 2 electrons.

Since we have already used 2 electrons in the 1st electron shell, now we have 112 – 2 = 110 electrons left. So in the next step, we have to draw the 2nd electron shell.

### Draw 2nd electron shell

The 2nd electron shell (containing s subshell and p subshell) can hold up to a maximum of 8 electrons. So draw the 2nd electron shell as follows:

In the above image, 2 represents the 2nd electron shell that contains 2s and 2p subshells. And the green and orange color represents the number of electrons in that subshell. This means that the 2nd electron shell has a total of 8 electrons.

Now we have already used 10 electrons in 1st and 2nd electron shells, so we have 112 – 10 = 102 electrons left. So in the next step, we have to draw the 3rd electron shell.

### Draw 3rd electron shell

The 3rd electron shell (containing s subshell, p subshell, and d subshell) can hold up to a maximum of 18 electrons. So draw the 3rd electron shell as follows:

In the above image, 3 represents the 3rd electron shell that contains 3s, 3p, and 3d subshells. And the green, orange, and pink color represents the number of electrons in that subshell. This means that the 3rd electron shell has a total of 18 electrons.

Now we have already used 28 electrons in 1st, 2nd, and 3rd electron shells, so we have 112 – 28 = 84 electrons left. So in the next step, we have to draw the 4th electron shell.

### Draw 4th electron shell

The 4th electron shell (containing s subshell, p subshell, d subshell, and f subshell) can hold up to a maximum of 32 electrons. So draw the 4th electron shell as follows:

In the above image, 4 represents the 4th electron shell that contains 4s, 4p, 4d, and 4f subshells. And the green, orange, pink, and blue color represents the number of electrons in that subshell. This means that the 4th electron shell has a total of 32 electrons.

Now we have already used 60 electrons in 1st, 2nd, 3rd, and 4th electron shells, so we have 112 – 60 = 52 electrons left. So in the next step, we have to draw the 5th electron shell.

### Draw 5th electron shell

The 5th electron shell can hold up to a maximum of 50 electrons. So draw the 5th electron shell as follows:

In the above image, 5 represents the 5th electron shell that contains 5s, 5p, 5d, and 5f subshells. And the green, orange, pink, and blue color represents the number of electrons in that subshell. This means that the 5th electron shell has a total of 32 electrons.

Now we have already used 92 electrons in 1st, 2nd, 3rd, 4th, and 5th electron shells, so we have 112 – 92 = 20 electrons left. So in the next step, we have to draw the 6th electron shell.

### Draw 6th electron shell

The 6th electron shell can hold up to a maximum of 72 electrons. So draw the 6th electron shell as follows:

In the above image, 6 represents the 6th electron shell that contains 6s, 6p, and 6d subshells. And the green, orange, and pink color represents the number of electrons in that subshell. This means that the 6th electron shell has a total of 18 electrons.

The 6th electron shell contains only 6s, 6p, and 6d subshells, and not a 6f subshell. This is because according to the aufbau principle, the 7s subshell is filled first and then 5f, 6d, 7p… and so on.

Now we have already used 110 electrons in 1st, 2nd, 3rd, 4th, 5th, and 6th electron shells, so we have 112 – 110 = 2 electrons left. So in the next step, we have to draw the 7th electron shell.

### Draw 7th electron shell

The 7th electron shell can hold up to a maximum of 98 electrons. So draw the 7th electron shell as follows:

In the above image, 7 represents the 7th electron shell that contains 7s subshell. And the green color represents the number of electrons in that subshell. This means that the 7th electron shell has a total of 2 electrons.

That’s it! This is the final Bohr model of copernicium atom as we have used all 112 electrons: 2 electrons in the 1st electron shell, 8 electrons in the 2nd electron shell, 18 electrons in the 3rd electron shell, 32 electrons in the 4th electron shell, 32 electrons in the 5th electron shell, 18 electrons in the 6th electron shell, and 2 electrons in the 7th electron shell.