S2Cl2 Lewis structure

S2Cl2 Lewis Structure
S2Cl2 Lewis structure | Image: Learnool

S2Cl2 (disulfur dichloride) has two sulfur atoms and two chlorine atoms.

In the S2Cl2 Lewis structure, there is a single bond between the two sulfur atoms, and each sulfur is attached with one chlorine atom. Each chlorine atom has three lone pairs, and each sulfur atom has two lone pairs.

Rough sketch

  • First, determine the total number of valence electrons
Periodic table | Image: Learnool

In the periodic table, sulfur lies in group 16, and chlorine lies in group 17.

Hence, sulfur has six valence electrons and chlorine has seven valence electrons.

Since S2Cl2 has two sulfur atoms and two chlorine atoms, so…

Valence electrons of two sulfur atoms = 6 × 2 = 12
Valence electrons of two chlorine atoms = 7 × 2 = 14

And the total valence electrons = 12 + 14 = 26

  • Second, find the total electron pairs

We have a total of 26 valence electrons. And when we divide this value by two, we get the value of total electron pairs.

Total electron pairs = total valence electrons ÷ 2

So the total electron pairs = 26 ÷ 2 = 13

  • Third, determine the central atom

We have to place the least electronegative atom at the center.

Since sulfur is less electronegative than chlorine, assume that the central atom is right sulfur (as there are two sulfur atoms present here).

Therefore, place sulfurs in the center and chlorines on either side.

  • And finally, draw the rough sketch
S2Cl2 Lewis Structure (Step 1)
Rough sketch of S2Cl2 Lewis structure | Image: Learnool

Lone pair

Here, we have a total of 13 electron pairs. And three bonds are already marked. So we have to only mark the remaining ten electron pairs as lone pairs on the sketch.

Also remember that both (sulfur and chlorine) are the period 3 elements, so they can keep more than 8 electrons in their last shell.

Always start to mark the lone pairs from outside atoms. Here, the outside atoms are chlorines and left sulfur.

So for each chlorine, there are three lone pairs, and for each sulfur, there are two lone pairs.

Mark the lone pairs on the sketch as follows:

S2Cl2 Lewis Structure (Step 2)
Lone pairs marked, and got the stable Lewis structure of S2Cl2 | Image: Learnool

Formal charge

Use the following formula to calculate the formal charges on atoms:

Formal charge = valence electrons – nonbonding electrons – ½ bonding electrons

For each sulfur atom, formal charge = 6 – 4 – ½ (4) = 0

For each chlorine atom, formal charge = 7 – 6 – ½ (2) = 0

Here, both sulfur and chlorine atoms do not have charges, so no need to mark the charges.

Final structure

The final structure of S2Cl2 consists of a central sulfur-sulfur single bond, with each sulfur atom also sharing a single covalent bond with a chlorine atom. In this staggered arrangement, both sulfur atoms satisfy the octet rule by maintaining two lone pairs each, while the terminal chlorine atoms complete their octets with three lone pairs. This specific connectivity results in formal charges of zero for all four atoms, representing the most stable and energetically favorable distribution of electrons. Consequently, this non-planar bonding pattern represents the definitive and accurate Lewis representation of disulfur dichloride.

Next: IBr Lewis structure

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Deep

Learnool.com was founded by Deep Rana, who is a mechanical engineer by profession and a blogger by passion. He has a good conceptual knowledge on different educational topics and he provides the same on this website. He loves to learn something new everyday and believes that the best utilization of free time is developing a new skill.

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