Selenium Bohr model

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In the selenium Bohr model, the nucleus consists of 34 protons and 45 neutrons. Surrounding this nucleus are four electron shells, accommodating a total of 34 electrons.

To draw the selenium Bohr model, outline the 34 protons, 45 neutrons, and 34 electrons. Start by illustrating the nucleus, and then draw the four electron shells. The first three shells should contain 2, 8, and 18 electrons, respectively, while the fourth shell holds the remaining 6 electrons.

Steps

Write protons, neutrons, and electrons of selenium atom

Selenium has 34 protons, 45 neutrons, and 34 electrons.

Learn how to find: Selenium protons neutrons electrons

Draw nucleus of selenium atom

The nucleus of a selenium atom contains 34 protons and 45 neutrons. So draw the nucleus of selenium atom as follows:

Now in the next step, draw the 1^st electron shell and start marking electrons.

Draw 1^st electron shell

Remember that we have a total of 34 electrons.

The 1^st electron shell (containing s subshell) can hold up to a maximum of 2 electrons. So draw the 1^st electron shell as follows:

In the above image, 1 represents the 1^st electron shell that contains 1s subshell. And the green color represents the number of electrons in that subshell. This means that the 1^st electron shell has a total of 2 electrons.

Since we have already used 2 electrons in the 1^st electron shell, now we have 34 – 2 = 32 electrons left. So in the next step, we have to draw the 2^nd electron shell.

Draw 2^nd electron shell

The 2^nd electron shell (containing s subshell and p subshell) can hold up to a maximum of 8 electrons. So draw the 2^nd electron shell as follows:

In the above image, 2 represents the 2^nd electron shell that contains 2s and 2p subshells. And the green and orange color represents the number of electrons in that subshell. This means that the 2^nd electron shell has a total of 8 electrons.

Now we have already used 10 electrons in 1^st and 2^nd electron shells, so we have 34 – 10 = 24 electrons left. So in the next step, we have to draw the 3^rd electron shell.

Draw 3^rd electron shell

The 3^rd electron shell (containing s subshell, p subshell, and d subshell) can hold up to a maximum of 18 electrons. So draw the 3^rd electron shell as follows:

In the above image, 3 represents the 3^rd electron shell that contains 3s, 3p and 3d subshells. And the green, orange, and pink color represents the number of electrons in that subshell. This means that the 3^rd electron shell has a total of 18 electrons.

Now we have already used 28 electrons in 1^st, 2^nd, and 3^rd electron shells, so we have 34 – 28 = 6 electrons left. So in the next step, we have to draw the 4^th electron shell.

Draw 4^th electron shell

The 4^th electron shell (containing s subshell, p subshell, d subshell, and f subshell) can hold up to a maximum of 32 electrons. So draw the 4^th electron shell as follows:

In the above image, 4 represents the 4^th electron shell that contains 4s and 4p subshells. And the green and orange color represents the number of electrons in that subshell. This means that the 4^th electron shell has a total of 6 electrons.

That’s it! This is the final Bohr model of selenium atom as we have used all 34 electrons: 2 electrons in the 1^st electron shell, 8 electrons in the 2^nd electron shell, 18 electrons in the 3^rd electron shell, and 6 electrons in the 4^th electron shell.

Next: Bromine Bohr model

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Related

• Selenium

More topics

• Selenium electron configuration
• Selenium orbital diagram
• Selenium protons neutrons electrons
• Selenium valence electrons

External links

• File:34 selenium (Se) enhanced Bohr model.png – Wikimedia Commons
• Chemical Elements.com – Selenium (Se) – Chemical Elements.com
• What is the Bohr model for Selenium? – Topblogtenz
• Selenium (Se) – Periodic Table – ChemicalAid