Aluminum Bohr model

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Aluminum Bohr model
Aluminum Bohr model

The Bohr model of aluminum contains a nucleus having 13 protons and 14 neutrons in the center, and around this nucleus, there are three electron shells containing 13 electrons.

Steps

Here’s how you can draw the Bohr model of aluminum step by step.

#1 Write protons, neutrons, and electrons of aluminum atom
#2 Draw nucleus of aluminum atom
#3 Draw 1st electron shell
#4 Draw 2nd electron shell
#5 Draw 3rd electron shell

Let’s break down each step in detail.

#1 Write protons, neutrons, and electrons of aluminum atom

Aluminum has 13 protons, 14 neutrons, and 13 electrons.

#2 Draw nucleus of aluminum atom

The nucleus of an aluminum atom contains 13 protons and 14 neutrons. So draw the nucleus of aluminum atom as follows:

Aluminum nucleus
Aluminum nucleus

Now in the next step, draw the 1st electron shell and start marking electrons.

#3 Draw 1st electron shell

Remember that we have a total of 13 electrons.

The 1st electron shell (containing s subshell) can hold up to a maximum of 2 electrons. So draw the 1st electron shell as follows:

Aluminum shell 1
Aluminum 1st electron shell drawn

In the above image, 1 represents the 1st electron shell that contains 1s subshell. And the green color represents the number of electrons in that subshell. This means that the 1st electron shell has a total of 2 electrons.

Since we have already used 2 electrons in the 1st electron shell, now we have 13 – 2 = 11 electrons left. So in the next step, we have to draw the 2nd electron shell.

#4 Draw 2nd electron shell

The 2nd electron shell (containing s subshell and p subshell) can hold up to a maximum of 8 electrons. So draw the 2nd electron shell as follows:

Aluminum shell 2
Aluminum 2nd electron shell drawn

In the above image, 2 represents the 2nd electron shell that contains 2s and 2p subshells. And the green and orange color represents the number of electrons in that subshell. This means that the 2nd electron shell has a total of 8 electrons.

Now we have already used 10 electrons in 1st and 2nd electron shells, so we have 13 – 10 = 3 electrons left. So in the next step, we have to draw the 3rd electron shell.

#5 Draw 3rd electron shell

The 3rd electron shell (containing s subshell, p subshell, and d subshell) can hold up to a maximum of 18 electrons. So draw the 3rd electron shell as follows:

Aluminum shell 3
Aluminum 3rd electron shell drawn

In the above image, 3 represents the 3rd electron shell that contains 3s and 3p subshells. And the green and orange color represents the number of electrons in that subshell. This means that the 3rd electron shell has a total of 3 electrons.

That’s it! This is the final Bohr model of aluminum atom as we have used all 13 electrons: 2 electrons in the 1st electron shell, 8 electrons in the 2nd electron shell, and 3 electrons in the 3rd electron shell.

Next: Silicon Bohr model

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Deep

Learnool.com was founded by Deep Rana, who is a mechanical engineer by profession and a blogger by passion. He has a good conceptual knowledge on different educational topics and he provides the same on this website. He loves to learn something new everyday and believes that the best utilization of free time is developing a new skill.

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