# Neon Bohr model

In the neon Bohr model, the nucleus comprises 10 protons and 10 neutrons. Orbiting this nucleus are two electron shells, containing a total of 10 electrons.

To draw the neon Bohr model, represent the 10 protons, 10 neutrons, and 10 electrons. Begin by sketching the nucleus, and then draw the two electron shells. Both shells should be fully occupied, with the first containing 2 electrons and the second holding the remaining 8 electrons.

Contents

## Steps

### Write protons, neutrons, and electrons of neon atom

Neon has 10 protons, 10 neutrons, and 10 electrons.

### Draw nucleus of neon atom

The nucleus of a neon atom contains 10 protons and 10 neutrons. So draw the nucleus of neon atom as follows:

Now in the next step, draw the 1st electron shell and start marking electrons.

### Draw 1st electron shell

Remember that we have a total of 10 electrons.

The 1st electron shell (containing s subshell) can hold up to a maximum of 2 electrons. So draw the 1st electron shell as follows:

In the above image, 1 represents the 1st electron shell that contains 1s subshell. And the green color represents the number of electrons in that subshell. This means that the 1st electron shell has a total of 2 electrons.

Since we have already used 2 electrons in the 1st electron shell, now we have 10 – 2 = 8 electrons left. So in the next step, we have to draw the 2nd electron shell.

### Draw 2nd electron shell

The 2nd electron shell (containing s subshell and p subshell) can hold up to a maximum of 8 electrons. So draw the 2nd electron shell as follows:

In the above image, 2 represents the 2nd electron shell that contains 2s and 2p subshells. And the green and orange color represents the number of electrons in that subshell. This means that the 2nd electron shell has a total of 8 electrons.

That’s it! This is the final Bohr model of neon atom as we have used all 10 electrons: 2 electrons in the 1st electron shell and 8 electrons in the 2nd electron shell.

Next: Aluminum Bohr model