BrCN Lewis structure

BrCN Lewis Structure
BrCN Lewis structure | Image: Learnool

BrCN (cyanogen bromide) has one bromine atom, one carbon atom, and one nitrogen atom.

In the BrCN Lewis structure, there is a single bond between carbon and bromine atom, and a triple bond between carbon and nitrogen atom. The bromine atom has three lone pairs, and the nitrogen atom has one lone pair.

Rough sketch

  • First, determine the total number of valence electrons
Periodic table | Image: Learnool

In the periodic table, bromine lies in group 17, carbon lies in group 14, and nitrogen lies in group 15.

Hence, bromine has seven valence electrons, carbon has four valence electrons, and nitrogen has five valence electrons.

Since BrCN has one bromine atom, one carbon atom, and one nitrogen atom, so…

Valence electrons of one bromine atom = 7 × 1 = 7
Valence electrons of one carbon atom = 4 × 1 = 4
Valence electrons of one nitrogen atom = 5 × 1 = 5

And the total valence electrons = 7 + 4 + 5 = 16

  • Second, find the total electron pairs

We have a total of 16 valence electrons. And when we divide this value by two, we get the value of total electron pairs.

Total electron pairs = total valence electrons ÷ 2

So the total electron pairs = 16 ÷ 2 = 8

  • Third, determine the central atom

We have to place the least electronegative atom at the center.

Since carbon is less electronegative than bromine and nitrogen, assume that the central atom is carbon.

Therefore, place carbon in the center and bromine and nitrogen on either side.

  • And finally, draw the rough sketch
BrCN Lewis Structure (Step 1)
Rough sketch of BrCN Lewis structure | Image: Learnool

Lone pair

Here, we have a total of 8 electron pairs. And two bonds are already marked. So we have to only mark the remaining six electron pairs as lone pairs on the sketch.

Also remember that bromine is a period 4 element, so it can keep more than 8 electrons in its last shell. And both (carbon and nitrogen) are the period 2 elements, so they can not keep more than 8 electrons in their last shell.

Always start to mark the lone pairs from outside atoms. Here, the outside atoms are bromine and nitrogen.

So for bromine and nitrogen, there are three lone pairs, and for carbon, there is zero lone pair because all six electron pairs are over.

Mark the lone pairs on the sketch as follows:

BrCN Lewis Structure (Step 2)
Lone pairs marked on BrCN Lewis structure | Image: Learnool

Formal charge

Use the following formula to calculate the formal charges on atoms:

Formal charge = valence electrons – nonbonding electrons – ½ bonding electrons

For bromine atom, formal charge = 7 – 6 – ½ (2) = 0

For carbon atom, formal charge = 4 – 0 – ½ (4) = +2

For nitrogen atom, formal charge = 5 – 6 – ½ (2) = -2

Here, both carbon and nitrogen atoms have charges, so mark them on the sketch as follows:

BrCN Lewis Structure (Step 3)
Formal charges marked on BrCN Lewis structure | Image: Learnool

The above structure is not a stable Lewis structure because both carbon and nitrogen atoms have charges. Therefore, reduce the charges (as below) by converting lone pairs to bonds.

Convert a lone pair of the nitrogen atom to make a new C — N bond with the carbon atom as follows:

BrCN Lewis Structure (Step 4)
Lone pair of nitrogen is converted, but still there are charges | Image: Learnool

Since there are charges on carbon and nitrogen atoms, again convert a lone pair of the nitrogen atom to make a new C — N bond with the carbon atom as follows:

BrCN Lewis Structure (Step 5)
Lone pair of nitrogen is converted again, and got the stable Lewis structure of BrCN | Image: Learnool

Final structure

The final structure of BrCN features a central carbon atom linked to a bromine atom and a nitrogen atom. In this arrangement, the carbon atom forms a single covalent bond with the bromine atom and a triple bond with the nitrogen atom to satisfy the octet rule. Within this layout, the bromine atom maintains three lone pairs, while the nitrogen atom retains one lone pair alongside its triple bond. This configuration represents the most stable state for the molecule because it results in a formal charge of zero for every atom involved. Accordingly, this specific electronic distribution serves as the definitive and most accurate Lewis representation of cyanogen bromide.

Next: BrCl Lewis structure

External video

External links

Deep

Learnool.com was founded by Deep Rana, who is a mechanical engineer by profession and a blogger by passion. He has a good conceptual knowledge on different educational topics and he provides the same on this website. He loves to learn something new everyday and believes that the best utilization of free time is developing a new skill.

Leave a Comment