C5H10 Lewis structure

C₅H₁₀ (cyclopentane) has five carbon atoms and ten hydrogen atoms.

In C₅H₁₀ Lewis structure, there are five single bonds between the five carbon atoms, and each carbon is attached with two hydrogen atoms. And none of the atoms has a lone pair.

Alternative method: Lewis structure of C₅H₁₀

Rough sketch

• First, determine the total number of valence electrons

In the periodic table, carbon lies in group 14, and hydrogen lies in group 1.

Hence, carbon has four valence electrons and hydrogen has one valence electron.

Since C₅H₁₀ has five carbon atoms and ten hydrogen atoms, so…

Valence electrons of five carbon atoms = 4 × 5 = 20
Valence electrons of ten hydrogen atoms = 1 × 10 = 10

And the total valence electrons = 20 + 10 = 30

Learn how to find: Carbon valence electrons and Hydrogen valence electrons

• Second, find the total electron pairs

We have a total of 30 valence electrons. And when we divide this value by two, we get the value of total electron pairs.

Total electron pairs = total valence electrons ÷ 2

So the total electron pairs = 30 ÷ 2 = 15

• Third, determine the central atom

Here hydrogen can not be the central atom. Because the central atom is bonded with at least two other atoms, and hydrogen has only one electron in its last shell, so it can not make more than one bond.

Now there are five atoms remaining and all five atoms are carbon, so we can assume any one as the central atom.

Let’s assume that the central atom is top carbon.

Therefore, place carbons in the center and hydrogens on either side.

• And finally, draw the rough sketch

Lone pair

Here, we have a total of 15 electron pairs. And fifteen bonds are already marked. So we do not have to mark any electron pair as a lone pair on the sketch.

Final structure

The final structure of C₅H₁₀ (specifically the cyclopentane isomer) consists of five carbon atoms arranged in a closed, five-membered ring through single covalent bonds. In this arrangement, each carbon atom within the ring is also single-bonded to two hydrogen atoms. Within this layout, every carbon atom satisfies the octet rule by forming four total bonds, while each hydrogen atom achieves its stable duet state. This cyclic configuration represents the most stable state for the molecule because it results in a formal charge of zero for every atom involved. Accordingly, this specific electronic distribution serves as the definitive and most accurate Lewis representation of cyclopentane.

Next: IBr₄^– Lewis structure

External video

• How to Draw the Lewis Dot Structure for C5​H10: Cyclopentane – YouTube • Wayne Breslyn

External links

• https://www.reddit.com/r/chemhelp/comments/qjt7z0/what_is_the_lewis_structure_and_3d_drawing_of/
• https://www.chegg.com/homework-help/questions-and-answers/draw-lewis-structure-c5h10-q16933075
• https://oneclass.com/homework-help/chemistry/7026800-c5h10-lewis-structure.en.html
• https://brainly.com/question/30157038