
HNO (nitroxyl) has one hydrogen atom, one nitrogen atom, and one oxygen atom.
In the HNO Lewis structure, there is a single bond between nitrogen and hydrogen atom, and a double bond between nitrogen and oxygen atom. The nitrogen atom has one lone pair, and the oxygen atom has two lone pairs.
Alternative method: Lewis structure of HNO
Rough sketch
- First, determine the total number of valence electrons

In the periodic table, hydrogen lies in group 1, nitrogen lies in group 15, and oxygen lies in group 16.
Hence, hydrogen has one valence electron, nitrogen has five valence electrons, and oxygen has six valence electrons.
Since HNO has one hydrogen atom, one nitrogen atom, and one oxygen atom, so…
Valence electrons of one hydrogen atom = 1 × 1 = 1
Valence electrons of one nitrogen atom = 5 × 1 = 5
Valence electrons of one oxygen atom = 6 × 1 = 6
And the total valence electrons = 1 + 5 + 6 = 12
Learn how to find: Hydrogen valence electrons, Nitrogen valence electrons, and Oxygen valence electrons
- Second, find the total electron pairs
We have a total of 12 valence electrons. And when we divide this value by two, we get the value of total electron pairs.
Total electron pairs = total valence electrons ÷ 2
So the total electron pairs = 12 ÷ 2 = 6
- Third, determine the central atom
Here hydrogen can not be the central atom. Because the central atom is bonded with at least two other atoms, and hydrogen has only one electron in its last shell, so it can not make more than one bond.
Now we have to choose the central atom from nitrogen and oxygen. Place the least electronegative atom at the center.
Since nitrogen is less electronegative than oxygen, assume that the central atom is nitrogen.
Therefore, place nitrogen in the center and hydrogen and oxygen on either side.
- And finally, draw the rough sketch

Lone pair
Here, we have a total of 6 electron pairs. And two bonds are already marked. So we have to only mark the remaining four electron pairs as lone pairs on the sketch.
Also remember that hydrogen is a period 1 element, so it can not keep more than 2 electrons in its last shell. And both (nitrogen and oxygen) are the period 2 elements, so they can not keep more than 8 electrons in their last shell.
Always start to mark the lone pairs from outside atoms. Here, the outside atoms are hydrogen and oxygen. But no need to mark on hydrogen, because hydrogen already has two electrons.
So for oxygen, there are three lone pairs, and for nitrogen, there is one lone pair.
Mark the lone pairs on the sketch as follows:

Formal charge
Use the following formula to calculate the formal charges on atoms:
Formal charge = valence electrons – nonbonding electrons – ½ bonding electrons
For hydrogen atom, formal charge = 1 – 0 – ½ (2) = 0
For nitrogen atom, formal charge = 5 – 2 – ½ (4) = +1
For oxygen atom, formal charge = 6 – 6 – ½ (2) = -1
Here, both nitrogen and oxygen atoms have charges, so mark them on the sketch as follows:

The above structure is not a stable Lewis structure because both nitrogen and oxygen atoms have charges. Therefore, reduce the charges (as below) by converting lone pairs to bonds.
Convert a lone pair of the oxygen atom to make a new N — O bond with the nitrogen atom as follows:

Final structure
The final structure of HNO features a central nitrogen atom connected to one oxygen atom and one hydrogen atom. In this configuration, the nitrogen atom forms a double bond with the oxygen atom and a single covalent bond with the hydrogen atom to fulfill the octet rule. Within this layout, the nitrogen atom maintains one lone pair, while the oxygen atom fulfills its octet by retaining two lone pairs. This arrangement represents the most stable state for the molecule because it results in a formal charge of zero for every atom involved. Accordingly, this specific electronic distribution serves as the definitive and most accurate Lewis representation of nitroxyl.
Next: NI3 Lewis structure
External video
- HNO Lewis Structure – YouTube • Wayne Breslyn
External links
Deep
Learnool.com was founded by Deep Rana, who is a mechanical engineer by profession and a blogger by passion. He has a good conceptual knowledge on different educational topics and he provides the same on this website. He loves to learn something new everyday and believes that the best utilization of free time is developing a new skill.