ICl Lewis structure

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ICl (iodine monochloride) has one iodine atom and one chlorine atom.

In the ICl Lewis structure, there is a single bond between the iodine and chlorine atoms, and on both iodine and chlorine atoms, there are three lone pairs.

Steps

Use these steps to correctly draw the ICl Lewis structure:

#1 First draw a rough sketch
#2 Mark lone pairs on the atoms
#3 Calculate and mark formal charges on the atoms, if required

Let’s discuss each step in more detail.

#1 First draw a rough sketch

• First, determine the total number of valence electrons

In the periodic table, both iodine and chlorine lie in group 17.

Hence, both iodine and chlorine have seven valence electrons.

Since ICl has one iodine atom and one chlorine atom, so…

Valence electrons of one iodine atom = 7 × 1 = 7
Valence electrons of one chlorine atom = 7 × 1 = 7

And the total valence electrons = 7 + 7 = 14

Learn how to find: Chlorine valence electrons

• Second, find the total electron pairs

We have a total of 14 valence electrons. And when we divide this value by two, we get the value of total electron pairs.

Total electron pairs = total valence electrons ÷ 2

So the total electron pairs = 14 ÷ 2 = 7

• Third, determine the central atom

We have to place the least electronegative atom at the center.

Since iodine is less electronegative than chlorine, assume that the central atom is iodine.

• And finally, draw the rough sketch

#2 Mark lone pairs on the atoms

Here, we have a total of 7 electron pairs. And one I — Cl bonds are already marked. So we have to only mark the remaining six electron pairs as lone pairs on the sketch.

Also remember that iodine is a period 5 element, so it can keep more than 8 electrons in its last shell. And chlorine is a period 3 element, so it can keep more than 8 electrons in its last shell.

Always start to mark the lone pairs from outside atoms. Here, the outside atom is chlorine.

So for each atom, there are three lone pairs.

Mark the lone pairs on the sketch as follows:

#3 Calculate and mark formal charges on the atoms, if required

Use the following formula to calculate the formal charges on atoms:

Formal charge = valence electrons – nonbonding electrons – ½ bonding electrons

For iodine atom, formal charge = 7 – 6 – ½ (2) = 0

For chlorine atom, formal charge = 7 – 6 – ½ (2) = 0

Here, both iodine and chlorine atoms do not have charges, so no need to mark the charges.

In the above structure, you can see that the central atom (iodine) forms an octet. And the outside atom (chlorine) also forms an octet. Hence, the octet rule is satisfied.

Therefore, this structure is the stable Lewis structure of ICl.

Next: C₂^2- Lewis structure

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External links

• https://www.thegeoexchange.org/chemistry/bonding/Lewis-Structures/ICl-lewis-structure.html
• https://lambdageeks.com/icl-lewis-structure/