SO2Cl2 Lewis structure

SO2Cl2 Lewis Structure
SO2Cl2 Lewis structure | Image: Learnool

SO2Cl2 (sulfuryl chloride) has one sulfur atom, two oxygen atoms, and two chlorine atoms.

In the SO2Cl2 Lewis structure, there are two single bonds and two double bonds around the sulfur atom, with two chlorine atoms and two oxygen atoms attached to it. Each chlorine atom has three lone pairs, and each oxygen atom has two lone pairs.

Rough sketch

  • First, determine the total number of valence electrons
Periodic table | Image: Learnool

In the periodic table, both sulfur and oxygen lie in group 16, and chlorine lies in group 17.

Hence, both sulfur and oxygen have six valence electrons, and chlorine has seven valence electrons.

Since SO2Cl2 has one sulfur atom, two oxygen atoms, and two chlorine atoms, so…

Valence electrons of one sulfur atom = 6 × 1 = 6
Valence electrons of two oxygen atoms = 6 × 2 = 12
Valence electrons of two chlorine atoms = 7 × 2 = 14

And the total valence electrons = 6 + 12 + 14 = 32

  • Second, find the total electron pairs

We have a total of 32 valence electrons. And when we divide this value by two, we get the value of total electron pairs.

Total electron pairs = total valence electrons ÷ 2

So the total electron pairs = 32 ÷ 2 = 16

  • Third, determine the central atom

We have to place the least electronegative atom at the center.

Since sulfur is less electronegative than oxygen and chlorine, assume that the central atom is sulfur.

Therefore, place sulfur in the center and oxygen and chlorine on either side.

  • And finally, draw the rough sketch
SO2Cl2 Lewis Structure (Step 1)
Rough sketch of SO2Cl2 Lewis structure | Image: Learnool

Lone pair

Here, we have a total of 16 electron pairs. And four bonds are already marked. So we have to only mark the remaining twelve electron pairs as lone pairs on the sketch.

Also remember that both (sulfur and chlorine) are the period 3 elements, so they can keep more than 8 electrons in their last shell. And oxygen is a period 2 element, so it can not keep more than 8 electrons in its last shell.

Always start to mark the lone pairs from outside atoms. Here, the outside atoms are oxygens and chlorines.

So for each oxygen and each chlorine, there are three lone pairs, and for sulfur, there is zero lone pair because all twelve electron pairs are over.

Mark the lone pairs on the sketch as follows:

SO2Cl2 Lewis Structure (Step 2)
Lone pairs marked on SO2Cl2 Lewis structure | Image: Learnool

Formal charge

Use the following formula to calculate the formal charges on atoms:

Formal charge = valence electrons – nonbonding electrons – ½ bonding electrons

For sulfur atom, formal charge = 6 – 0 – ½ (8) = +2

For each oxygen atom, formal charge = 6 – 6 – ½ (2) = -1

For each chlorine atom, formal charge = 7 – 6 – ½ (2) = 0

Here, both sulfur and oxygen atoms have charges, so mark them on the sketch as follows:

SO2Cl2 Lewis Structure (Step 3)
Formal charges marked on SO2Cl2 Lewis structure | Image: Learnool

The above structure is not a stable Lewis structure because both sulfur and oxygen atoms have charges. Therefore, reduce the charges (as below) by converting lone pairs to bonds.

Convert a lone pair of the oxygen atom to make a new S — O bond with the sulfur atom as follows:

SO2Cl2 Lewis Structure (Step 4)
Lone pair of top oxygen is converted, but still there are charges | Image: Learnool

Since there are charges on sulfur and oxygen atoms, again convert a lone pair of the oxygen atom to make a new S — O bond with the sulfur atom as follows:

SO2Cl2 Lewis Structure (Step 5)
Lone pair of left oxygen is converted, and got the stable Lewis structure of SO2Cl2 | Image: Learnool

Final structure

The final structure of SO2Cl2 comprises a central sulfur atom linked to two oxygen atoms and two chlorine atoms. In this configuration, the sulfur atom utilizes an expanded valence shell to form double bonds with both oxygen atoms and single covalent bonds with both chlorine atoms. Within this layout, each oxygen atom fulfills its octet by retaining two lone pairs, while each chlorine atom stays stable by maintaining three lone pairs alongside its single shared bond. This arrangement represents the most stable state for the molecule because it results in a formal charge of zero for every atom involved. Accordingly, this specific electronic distribution serves as the definitive and most accurate Lewis representation of sulfuryl chloride.

Next: Lewis structure of ClO2

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Deep

Learnool.com was founded by Deep Rana, who is a mechanical engineer by profession and a blogger by passion. He has a good conceptual knowledge on different educational topics and he provides the same on this website. He loves to learn something new everyday and believes that the best utilization of free time is developing a new skill.

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