Sodium Bohr model

The Bohr model of sodium consists of a central nucleus containing 11 protons and 12 neutrons.^[1][2][3] This nucleus is surrounded by three electron shells that hold a total of 11 electrons. The electrons are arranged in the shells according to energy levels, with the first shell (K shell) holding 2 electrons, the second shell (L shell) holding 8 electrons, and the third shell (M shell) containing the remaining 1 electron.

To draw the Bohr model of sodium, start by sketching the nucleus in the center, indicating the 11 protons and 12 neutrons. Next, draw three concentric electron shells around the nucleus. Place 2 electrons in the K shell, 8 electrons in the L shell, and 1 electron in the M shell. Label the shells as K, L, and M to indicate their sequence from the nucleus outward, completing the atomic structure of sodium.

Steps

Write protons, neutrons, and electrons of sodium atom

Sodium has 11 protons, 12 neutrons, and 11 electrons.

Learn how to find: Sodium protons neutrons electrons

Draw nucleus of sodium atom

The nucleus of a sodium atom contains 11 protons and 12 neutrons. So draw the nucleus of sodium atom as follows:

Now in the next step, draw the 1^st electron shell and start marking electrons.

Draw 1^st electron shell

Remember that we have a total of 11 electrons.

The 1^st electron shell (containing s subshell) can hold up to a maximum of 2 electrons. So draw the 1^st electron shell as follows:

In the above image, 1 represents the 1^st electron shell that contains 1s subshell. And the green color represents the number of electrons in that subshell. This means that the 1^st electron shell has a total of 2 electrons.

Since we have already used 2 electrons in the 1^st electron shell, now we have 11 – 2 = 9 electrons left. So in the next step, we have to draw the 2^nd electron shell.

Draw 2^nd electron shell

The 2^nd electron shell (containing s subshell and p subshell) can hold up to a maximum of 8 electrons. So draw the 2^nd electron shell as follows:

In the above image, 2 represents the 2^nd electron shell that contains 2s and 2p subshells. And the green and orange color represents the number of electrons in that subshell. This means that the 2^nd electron shell has a total of 8 electrons.

Now we have already used 10 electrons in 1^st and 2^nd electron shells, so we have 11 – 10 = 1 electron left. So in the next step, we have to draw the 3^rd electron shell.

Draw 3^rd electron shell

The 3^rd electron shell (containing s subshell, p subshell, and d subshell) can hold up to a maximum of 18 electrons. So draw the 3^rd electron shell as follows:

In the above image, 3 represents the 3^rd electron shell that contains 3s subshell. And the green color represents the number of electrons in that subshell. This means that the 3^rd electron shell has a total of 1 electron.

That’s it! This is the final Bohr model of sodium atom as we have used all 11 electrons: 2 electrons in the 1^st electron shell, 8 electrons in the 2^nd electron shell, and 1 electron in the 3^rd electron shell.

Next: Magnesium Bohr model

Related

• Sodium

More topics

• Sodium orbital diagram
• Sodium protons neutrons electrons
• Sodium valence electrons

References