
CFCl3 (trichlorofluoromethane) has one carbon atom, one fluorine atom, and three chlorine atoms.
In CFCl3 Lewis structure, there are four single bonds around the carbon atom, with three chlorine atoms and one fluorine atom attached to it. And the fluorine atom and each chlorine atom has three lone pairs.
Alternative method: Lewis structure of CFCl3
Rough sketch
- First, determine the total number of valence electrons

In the periodic table, carbon lies in group 14, and both fluorine and chlorine lie in group 17.
Hence, carbon has four valence electrons, and both fluorine and chlorine have seven valence electrons.
Since CFCl3 has one carbon atom, one fluorine atom, and three chlorine atoms, so…
Valence electrons of one carbon atom = 4 × 1 = 4
Valence electrons of one fluorine atom = 7 × 1 = 7
Valence electrons of three chlorine atoms = 7 × 3 = 21
And the total valence electrons = 4 + 7 + 21 = 32
Learn how to find: Carbon valence electrons, Fluorine valence electrons, and Chlorine valence electrons
- Second, find the total electron pairs
We have a total of 32 valence electrons. And when we divide this value by two, we get the value of total electron pairs.
Total electron pairs = total valence electrons ÷ 2
So the total electron pairs = 32 ÷ 2 = 16
- Third, determine the central atom
We have to place the least electronegative atom at the center.
Since carbon is less electronegative than fluorine and chlorine, assume that the central atom is carbon.
Therefore, place carbon in the center and fluorine and chlorine on either side.
- And finally, draw the rough sketch

Lone pair
Here, we have a total of 16 electron pairs. And four bonds are already marked. So we have to only mark the remaining twelve electron pairs as lone pairs on the sketch.
Also remember that both (carbon and fluorine) are the period 2 elements, so they can not keep more than 8 electrons in their last shell. And chlorine is a period 3 element, so it can keep more than 8 electrons in its last shell.
Always start to mark the lone pairs from outside atoms. Here, the outside atoms are fluorine and chlorines.
So for fluorine and each chlorine, there are three lone pairs, and for carbon, there is zero lone pair because all twelve electron pairs are over.
Mark the lone pairs on the sketch as follows:

Formal charge
Use the following formula to calculate the formal charges on atoms:
Formal charge = valence electrons – nonbonding electrons – ½ bonding electrons
For carbon atom, formal charge = 4 – 0 – ½ (8) = 0
For fluorine and each chlorine atom, formal charge = 7 – 6 – ½ (2) = 0
Here, the atoms do not have charges, so no need to mark the charges.
Final structure
The final structure of CFCl3 includes a central carbon atom connected to one fluorine atom and three chlorine atoms through single covalent bonds. In this arrangement, the carbon atom achieves a stable octet by sharing its four valence electrons with the four halogen atoms. Within this layout, the fluorine atom and all three chlorine atoms fulfill the octet rule by maintaining three lone pairs alongside their respective single bonds. This tetrahedral configuration represents the most stable state for the molecule because it results in a formal charge of zero for every atom involved. Accordingly, this specific electronic distribution serves as the definitive and most accurate Lewis representation of trichlorofluoromethane (also known as Freon-11).
Next: NCl2– Lewis structure
External video
- How to Draw the Lewis Structure for CFCl3 – YouTube • Wayne Breslyn
External links
- https://lambdageeks.com/cfcl3-lewis-structure/
- https://www.numerade.com/ask/question/cfcl3-i-need-draw-lewis-dot-structures-and-give-the-shapes-molecule-geometry-62396/
- https://oneclass.com/homework-help/chemistry/7026532-cfcl3-lewis-structure.en.html
- https://www.chegg.com/homework-help/questions-and-answers/following-pairs-substances-draw-lewis-structures-indicate-pair-polar-explain–chcl3-cfcl3–q17250457
Deep
Learnool.com was founded by Deep Rana, who is a mechanical engineer by profession and a blogger by passion. He has a good conceptual knowledge on different educational topics and he provides the same on this website. He loves to learn something new everyday and believes that the best utilization of free time is developing a new skill.