SO2F2 Lewis structure

SO2F2 Lewis Structure
SO2F2 Lewis structure | Image: Learnool

SO2F2 (sulfuryl fluoride) has one sulfur atom, two oxygen atoms, and two fluorine atoms.

In SO2F2 Lewis structure, there are two double bonds and two single bonds around the sulfur atom, with two oxygen atoms and two fluorine atoms attached to it. Each oxygen atom has two lone pairs, and each fluorine atom has three lone pairs.

Rough sketch

  • First, determine the total number of valence electrons
Periodic table | Image: Learnool

In the periodic table, both sulfur and oxygen lie in group 16, and fluorine lies in group 17.

Hence, both sulfur and oxygen have six valence electrons, and fluorine has seven valence electrons.

Since SO2F2 has one sulfur atom, two oxygen atoms, and two fluorine atoms, so…

Valence electrons of one sulfur atom = 6 × 1 = 6
Valence electrons of two oxygen atoms = 6 × 2 = 12
Valence electrons of two fluorine atoms = 7 × 2 = 14

And the total valence electrons = 6 + 12 + 14 = 32

  • Second, find the total electron pairs

We have a total of 32 valence electrons. And when we divide this value by two, we get the value of total electron pairs.

Total electron pairs = total valence electrons ÷ 2

So the total electron pairs = 32 ÷ 2 = 16

  • Third, determine the central atom

We have to place the least electronegative atom at the center.

Since sulfur is less electronegative than oxygen and fluorine, assume that the central atom is sulfur.

Therefore, place sulfur in the center and oxygen and fluorine on either side.

  • And finally, draw the rough sketch
SO2F2 Lewis Structure (Step 1)
Rough sketch of SO2F2 Lewis structure | Image: Learnool

Lone pair

Here, we have a total of 16 electron pairs. And four bonds are already marked. So we have to only mark the remaining twelve electron pairs as lone pairs on the sketch.

Also remember that sulfur is a period 3 element, so it can keep more than 8 electrons in its last shell. And both (oxygen and fluorine) are the period 2 elements, so they can not keep more than 8 electrons in their last shell.

Always start to mark the lone pairs from outside atoms. Here, the outside atoms are oxygens and fluorines.

So for each oxygen and each fluorine, there are three lone pairs, and for sulfur, there is zero lone pair because all twelve electron pairs are over.

Mark the lone pairs on the sketch as follows:

SO2F2 Lewis Structure (Step 2)
Lone pairs marked on SO2F2 Lewis structure | Image: Learnool

Formal charge

Use the following formula to calculate the formal charges on atoms:

Formal charge = valence electrons – nonbonding electrons – ½ bonding electrons

For sulfur atom, formal charge = 6 – 0 – ½ (8) = +2

For each oxygen atom, formal charge = 6 – 6 – ½ (2) = -1

For each fluorine atom, formal charge = 7 – 6 – ½ (2) = 0

Here, both sulfur and oxygen atoms have charges, so mark them on the sketch as follows:

SO2F2 Lewis Structure (Step 3)
Formal charges marked on SO2F2 Lewis structure | Image: Learnool

The above structure is not a stable Lewis structure because both sulfur and oxygen atoms have charges. Therefore, reduce the charges (as below) by converting lone pairs to bonds.

Convert a lone pair of the oxygen atom to make a new S — O bond with the sulfur atom as follows:

SO2F2 Lewis Structure (Step 4)
Lone pair of left oxygen is converted, but still there are charges | Image: Learnool

Since there are charges on sulfur and oxygen atoms, again convert a lone pair of the oxygen atom to make a new S — O bond with the sulfur atom as follows:

SO2F2 Lewis Structure (Step 5)
Lone pair of top oxygen is converted, and got the stable Lewis structure of SO2F2 | Image: Learnool

Final structure

The final structure of SO2F2 involves a central sulfur atom connected to two oxygen atoms and two fluorine atoms. In this setup, the sulfur atom serves as an exception to the octet rule, utilizing an expanded valence shell to accommodate twelve electrons by forming double bonds with both oxygen atoms and single bonds with both fluorine atoms. Each oxygen atom fulfills its octet by retaining two lone pairs, while each fluorine atom maintains three lone pairs alongside its single bond. This arrangement is the most stable because it results in formal charges of zero for all atoms, representing the most energetically favorable state for the molecule. Accordingly, this specific electronic distribution serves as the definitive and most accurate Lewis representation of sulfuryl fluoride.

Next: POBr3 Lewis structure

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Deep

Learnool.com was founded by Deep Rana, who is a mechanical engineer by profession and a blogger by passion. He has a good conceptual knowledge on different educational topics and he provides the same on this website. He loves to learn something new everyday and believes that the best utilization of free time is developing a new skill.

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