C3H6 Lewis structure

C3H6 Lewis Structure
C3H6 Lewis structure | Image: Learnool

C3H6 (propene) has three carbon atoms and six hydrogen atoms.

In the C3H6 Lewis structure, there is one double bond and one single bond between the three carbon atoms. The left carbon is attached with two hydrogen atoms, the center carbon is attached with one hydrogen atom, and the right carbon is attached with three hydrogen atoms. And none of the atoms has a lone pair.

Rough sketch

  • First, determine the total number of valence electrons
Periodic table | Image: Learnool

In the periodic table, carbon lies in group 14, and hydrogen lies in group 1.

Hence, carbon has four valence electrons and hydrogen has one valence electron.

Since C3H6 has three carbon atoms and six hydrogen atoms, so…

Valence electrons of three carbon atoms = 4 × 3 = 12
Valence electrons of six hydrogen atoms = 1 × 6 = 6

And the total valence electrons = 12 + 6 = 18

  • Second, find the total electron pairs

We have a total of 18 valence electrons. And when we divide this value by two, we get the value of total electron pairs.

Total electron pairs = total valence electrons ÷ 2

So the total electron pairs = 18 ÷ 2 = 9

  • Third, determine the central atom

Here hydrogen can not be the central atom. Because the central atom is bonded with at least two other atoms, and hydrogen has only one electron in its last shell, so it can not make more than one bond.

Now there are three atoms remaining and all three atoms are carbon, so we can assume any one as the central atom.

Let’s assume that the central atom is center carbon.

Therefore, place carbons in the center and hydrogens on either side.

  • And finally, draw the rough sketch
C3H6 Lewis Structure (Step 1)
Rough sketch of C3H6 Lewis structure | Image: Learnool

Lone pair

Here, we have a total of 9 electron pairs. And eight bonds are already marked. So we have to only mark the remaining one electron pair as a lone pair on the sketch.

Also remember that carbon is a period 2 element, so it can not keep more than 8 electrons in its last shell. And hydrogen is a period 1 element, so it can not keep more than 2 electrons in its last shell.

Always start to mark the lone pairs from outside atoms. Here, the outside atoms are hydrogens, left carbon, and right carbon. But no need to mark on hydrogen, because each hydrogen has already two electrons.

So for left carbon, there is one lone pair, and for other two carbons, there is zero lone pair because all electron pairs are over.

Mark the lone pairs on the sketch as follows:

C3H6 Lewis Structure (Step 2)
Lone pairs marked on C3H6 Lewis structure | Image: Learnool

Formal charge

Use the following formula to calculate the formal charges on atoms:

Formal charge = valence electrons – nonbonding electrons – ½ bonding electrons

For left carbon atom, formal charge = 4 – 2 – ½ (6) = -1

For center carbon atom, formal charge = 4 – 0 – ½ (6) = +1

For right carbon atom, formal charge = 4 – 0 – ½ (8) = 0

For each hydrogen atom, formal charge = 1 – 0 – ½ (2) = 0

Here, both left carbon and center carbon atoms have charges, so mark them on the sketch as follows:

C3H6 Lewis Structure (Step 3)
Formal charges marked on C3H6 Lewis structure | Image: Learnool

The above structure is not a stable Lewis structure because both left carbon and center carbon atoms have charges. Therefore, reduce the charges (as below) by converting lone pairs to bonds.

Convert a lone pair of the left carbon atom to make a new C — C bond with the center carbon atom as follows:

C3H6 Lewis Structure (Step 4)
Lone pair of left carbon is converted, and got the stable Lewis structure of C3H6 | Image: Learnool

Final structure

The final structure of C3H6 includes three carbon atoms where two are connected by a double covalent bond and the others are linked by single bonds. In this configuration, the first carbon is single-bonded to two hydrogen atoms and double-bonded to the middle carbon, while the middle carbon is single-bonded to one hydrogen and one carbon atom. The third carbon atom satisfies the octet rule by forming single bonds with three hydrogen atoms and the central carbon. Within this layout, every carbon atom achieves four total bonds and every hydrogen atom reaches its stable duet state. This arrangement represents the most stable state for the molecule because it results in a formal charge of zero for every atom involved. Thus, this specific electronic distribution serves as the definitive and most accurate Lewis representation of propene.

Next: HOCl Lewis structure

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Deep

Learnool.com was founded by Deep Rana, who is a mechanical engineer by profession and a blogger by passion. He has a good conceptual knowledge on different educational topics and he provides the same on this website. He loves to learn something new everyday and believes that the best utilization of free time is developing a new skill.

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