# H2O2 Lewis structure

H2O2 (hydrogen peroxide) has two hydrogen atoms and two oxygen atoms.

In the H2O2 Lewis structure, there is a single bond between the two oxygen atoms, and each oxygen is attached with one hydrogen atom, and on each oxygen atom, there are two lone pairs.

Contents

## Steps

Here’s how you can easily draw the H2O2 Lewis structure step by step:

#1 Draw a rough skeleton structure
#2 Mention lone pairs on the atoms
#3 If needed, mention formal charges on the atoms

Now, let’s take a closer look at each step mentioned above.

### #1 Draw a rough skeleton structure

• First, determine the total number of valence electrons

In the periodic table, hydrogen lies in group 1, and oxygen lies in group 16.

Hence, hydrogen has one valence electron and oxygen has six valence electrons.

Since H2O2 has two hydrogen atoms and two oxygen atoms, so…

Valence electrons of two hydrogen atoms = 1 × 2 = 2
Valence electrons of two oxygen atoms = 6 × 2 = 12

And the total valence electrons = 2 + 12 = 14

• Second, find the total electron pairs

We have a total of 14 valence electrons. And when we divide this value by two, we get the value of total electron pairs.

Total electron pairs = total valence electrons ÷ 2

So the total electron pairs = 14 ÷ 2 = 7

• Third, determine the central atom

Here hydrogen can not be the central atom. Because the central atom is bonded with at least two other atoms, and hydrogen has only one electron in its last shell, so it can not make more than one bond.

Now there are only two atoms remaining and both atoms are oxygen, so we can assume any one as the central atom.

Let’s assume that the central atom is right oxygen.

Therefore, place oxygens in the center and hydrogens on either side.

• And finally, draw the rough sketch

### #2 Mention lone pairs on the atoms

Here, we have a total of 7 electron pairs. And three bonds are already marked. So we have to only mark the remaining four electron pairs as lone pairs on the sketch.

Also remember that hydrogen is a period 1 element, so it can not keep more than 2 electrons in its last shell. And oxygen is a period 2 element, so it can not keep more than 8 electrons in its last shell.

Always start to mark the lone pairs from outside atoms. Here, the outside atoms are hydrogens and left oxygen. But no need to mark on hydrogen, because each hydrogen has already two electrons.

So for left oxygen and right oxygen, there are two lone pairs.

Mark the lone pairs on the sketch as follows:

### #3 If needed, mention formal charges on the atoms

Use the following formula to calculate the formal charges on atoms:

Formal charge = valence electrons – nonbonding electrons – ½ bonding electrons

For each hydrogen atom, formal charge = 1 – 0 – ½ (2) = 0

For each oxygen atom, formal charge = 6 – 4 – ½ (4) = 0

Here, both hydrogen and oxygen atoms do not have charges, so no need to mark the charges.

In the above structure, you can see that the central atom (right oxygen) forms an octet. The outside atom (left oxygen) also forms an octet, and both hydrogens form a duet. Hence, the octet rule and duet rule are satisfied.

Therefore, this structure is the stable Lewis structure of H2O2.

Next: F2 Lewis structure