
OCS (carbonyl sulfide) has one oxygen atom, one carbon atom, and one sulfur atom.
In the OCS Lewis structure, there are two double bonds around the carbon atom, with oxygen and sulfur atoms attached to it, and on both oxygen and sulfur atoms, there are two lone pairs.
Alternative method: Lewis structure of OCS
Rough sketch
- First, determine the total number of valence electrons

In the periodic table, both oxygen and sulfur lie in group 16, and carbon lies in group 14.
Hence, both oxygen and sulfur have six valence electrons, and carbon has four valence electrons.
Since OCS has one oxygen atom, one carbon atom, and one sulfur atom, so…
Valence electrons of one oxygen atom = 6 × 1 = 6
Valence electrons of one carbon atom = 6 × 1 = 6
Valence electrons of one sulfur atom = 4 × 1 = 4
And the total valence electrons = 6 + 6 + 4 = 16
Learn how to find: Oxygen valence electrons, Carbon valence electrons, and Sulfur valence electrons
- Second, find the total electron pairs
We have a total of 16 valence electrons. And when we divide this value by two, we get the value of total electron pairs.
Total electron pairs = total valence electrons ÷ 2
So the total electron pairs = 16 ÷ 2 = 8
- Third, determine the central atom
We have to place the least electronegative atom at the center.
Since carbon is less electronegative than oxygen and sulfur, assume that the central atom is carbon.
Therefore, place carbon in the center and oxygen and sulfur on either side.
- And finally, draw the rough sketch

Lone pair
Here, we have a total of 8 electron pairs. And two bonds are already marked. So we have to only mark the remaining six electron pairs as lone pairs on the sketch.
Also remember that both (oxygen and carbon) are the period 2 elements, so they can not keep more than 8 electrons in their last shell. And sulfur is a period 3 element, so it can keep more than 8 electrons in its last shell.
Always start to mark the lone pairs from outside atoms. Here, the outside atoms are oxygen and sulfur.
So for oxygen and sulfur, there are three lone pairs, and for carbon, there is zero lone pair because all six electron pairs are over.
Mark the lone pairs on the sketch as follows:

Formal charge
Use the following formula to calculate the formal charges on atoms:
Formal charge = valence electrons – nonbonding electrons – ½ bonding electrons
For oxygen and sulfur atom, formal charge = 6 – 6 – ½ (2) = -1
For carbon atom, formal charge = 4 – 0 – ½ (4) = +2
Here, all three atoms have charges, so mark them on the sketch as follows:

The above structure is not a stable Lewis structure because all three atoms have charges. Therefore, reduce the charges (as below) by converting lone pairs to bonds.
Convert a lone pair of the oxygen atom to make a new C — O bond with the carbon atom as follows:

Since there are charges on carbon and sulfur atoms, again convert a lone pair of the sulfur atom to make a new C — S bond with the carbon atom as follows:

Final structure
The final structure of OCS includes a central carbon atom linked to one oxygen atom and one sulfur atom. In this arrangement, the carbon atom forms a double bond with both the oxygen and the sulfur atom to satisfy the octet rule. Within this layout, the oxygen atom maintains two lone pairs, while the sulfur atom also fulfills its octet by retaining two lone pairs alongside its double shared bond. This configuration represents the most stable state for the molecule because it results in a formal charge of zero for every atom involved. Accordingly, this specific electronic distribution serves as the definitive and most accurate Lewis representation of carbonyl sulfide.
Next: Br3– Lewis structure
External video
- OCS Lewis Structure: How to Draw the Lewis Structure for OCS – YouTube • Wayne Breslyn
External links
- https://www.thegeoexchange.org/chemistry/bonding/Lewis-Structures/OCS-Lewis-structure.html
- https://lambdageeks.com/ocs-lewis-structure/
- https://techiescientist.com/ocs-lewis-structure/
- https://socratic.org/questions/what-is-the-lewis-structure-of-ocs
Deep
Learnool.com was founded by Deep Rana, who is a mechanical engineer by profession and a blogger by passion. He has a good conceptual knowledge on different educational topics and he provides the same on this website. He loves to learn something new everyday and believes that the best utilization of free time is developing a new skill.