Vanadium electron configuration

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The vanadium electron configuration, represented as [Ar] 4s² 3d³ or 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d³, illustrates the precise arrangement of electrons within the atom. This configuration can be determined through various methods, including the aufbau principle, periodic table organization, Bohr model representation, or orbital diagram visualization.

Contents

Methods

Aufbau principle

First, find electrons of vanadium atom

The atomic number of vanadium represents the total number of electrons of vanadium. Since the atomic number of vanadium is 23, the total electrons of vanadium are 23.

Second, make a table of subshell and its maximum electrons

Calculate the maximum number of electrons each subshell can hold using the formula: 4ℓ + 2

Where, ℓ = azimuthal quantum number of the subshell

For s subshell, ℓ = 0
For p subshell, ℓ = 1
For d subshell, ℓ = 2
For f subshell, ℓ = 3

subshell	max. electrons
s	2
p	6
d	10
f	14

This means that,

Each s subshell can hold maximum 2 electrons
Each p subshell can hold maximum 6 electrons
Each d subshell can hold maximum 10 electrons
Each f subshell can hold maximum 14 electrons

Finally, use aufbau chart and start writing electron configuration

Remember that we have a total of 23 electrons.

According to the aufbau principle, 1s subshell is filled first and then 2s, 2p, 3s… and so on.

Use 2 electrons for 1s subshell | Image: Learnool

By looking at the chart, you can see that electrons are first filled in 1s subshell. Each s-subshell can hold a maximum of 2 electrons, so we will use 2 electrons for the 1s subshell.

So the electron configuration will be 1s². Where, 1s² indicates that the 1s subshell has 2 electrons.

Now we have used 2 electrons in the 1s subshell, so we have a total of 23 – 2 = 21 electrons left.

Use 2 electrons for 2s subshell | Image: Learnool

Looking at the chart, after 1s subshell now comes 2s subshell. Again, each s-subshell can hold a maximum of 2 electrons, so we will use 2 electrons for the 2s subshell.

So the electron configuration will be 1s² 2s². Where, 2s² indicates that the 2s subshell has 2 electrons.

Again, we have used 2 electrons in the 2s subshell, so we have a total of 21 – 2 = 19 electrons left.

Use 6 electrons for 2p subshell | Image: Learnool

After 2s subshell now comes 2p subshell. Each p-subshell can hold a maximum of 6 electrons, so we will use 6 electrons for the 2p subshell.

So the electron configuration will be 1s² 2s² 2p⁶. Where, 2p⁶ indicates that the 2p subshell has 6 electrons.

Here, we have used 6 electrons in the 2p subshell, so we have a total of 19 – 6 = 13 electrons left.

Use 2 electrons for 3s subshell | Image: Learnool

After 2p subshell now comes 3s subshell. Each s-subshell can hold a maximum of 2 electrons, so we will use 2 electrons for the 3s subshell.

So the electron configuration will be 1s² 2s² 2p⁶ 3s². Where, 3s² indicates that the 3s subshell has 2 electrons.

Here, we have used 2 electrons in the 3s subshell, so we have a total of 13 – 2 = 11 electrons left.

Use 6 electrons for 3p subshell | Image: Learnool

After 3s subshell now comes 3p subshell. Each p-subshell can hold a maximum of 6 electrons, so we will use 6 electrons for the 3p subshell.

So the electron configuration will be 1s² 2s² 2p⁶ 3s² 3p⁶. Where, 3p⁶ indicates that the 3p subshell has 6 electrons.

Here, we have used 6 electrons in the 3p subshell, so we have a total of 11 – 6 = 5 electrons left.

Use 2 electrons for 4s subshell | Image: Learnool

After 3p subshell now comes 4s subshell. Each s-subshell can hold a maximum of 2 electrons, so we will use 2 electrons for the 4s subshell.

So the electron configuration will be 1s² 2s² 2p⁶ 3s² 3p⁶ 4s². Where, 4s² indicates that the 4s subshell has 2 electrons.

Here, we have used 2 electrons in the 4s subshell, so we have a total of 5 – 2 = 3 electrons left.

Use last 3 electrons for 3d subshell | Image: Learnool

After 4s subshell now comes 3d subshell. Each d-subshell can hold a maximum of 10 electrons, but here we have only 3 electrons left, so we will use that 3 electrons for the 3d subshell.

So the electron configuration will be 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d³. Where, 3d³ indicates that the 3d subshell has 3 electrons.

Therefore, the final electron configuration of vanadium is 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d³. And the condensed/abbreviated electron configuration of vanadium is [Ar] 4s² 3d³.

Where, Ar is argon

Periodic table

First, get periodic table chart with spdf notation

The above image shows periodic table blocks.

The ‘s’ in s block represents that all s block elements have their valence electrons in s subshell. Similarly, the ‘p’ in p block represents that all p block elements have their valence electrons in p subshell. And so on for d block and f block.

Second, mark location of vanadium on periodic table

Vanadium is the d block element located in group 5 and period 4. Hence, mark the location of vanadium on the periodic table as follows:

Mark location of vanadium on periodic table | Image: Learnool

Finally, start writing electron configuration

Remember that: each s subshell can hold maximum 2 electrons, each p subshell can hold maximum 6 electrons, each d subshell can hold maximum 10 electrons, and each f subshell can hold maximum 14 electrons.

Start writing electron configuration from the very first element (i.e., hydrogen) all the way up to vanadium.

Start from 1s and write till V for full electron configuration | Image: Learnool

So the electron configuration of vanadium will be 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d³.

Bohr model

In the above image, 1 represents the 1^st electron shell. Similarly, 2 represents the 2^nd electron shell, 3 represents the 3^rd electron shell, and 4 represents the 4^th electron shell.

The 1^st electron shell contains 1s subshell, the 2^nd electron shell contains 2s and 2p subshells, the 3^rd electron shell contains 3s, 3p, and 3d subshells, the 4^th electron shell contains 4s subshell.

We know that each s subshell can hold maximum 2 electrons, each p subshell can hold maximum 6 electrons, each d subshell can hold maximum 10 electrons, and each f subshell can hold maximum 14 electrons.

Also, we have to make sure that the electron configuration will match the order of aufbau principle (i.e., the 1s subshell is filled first and then 2s, 2p, 3s… and so on).

So the electron configuration of vanadium will be 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d³.

Where,

1s² indicates that the 1s subshell has 2 electrons
2s² indicates that the 2s subshell has 2 electrons
2p⁶ indicates that the 2p subshell has 6 electrons
3s² indicates that the 3s subshell has 2 electrons
3p⁶ indicates that the 3p subshell has 6 electrons
4s² indicates that the 4s subshell has 2 electrons
3d³ indicates that the 3d subshell has 3 electrons

Learn how to draw: Vanadium Bohr model

Orbital diagram

The above orbital diagram shows that the 1s subshell has 2 electrons, the 2s subshell has 2 electrons, the 2p subshell has 6 electrons, the 3s subshell has 2 electrons, the 3p subshell has 6 electrons, the 4s subshell has 2 electrons, and the 3d subshell has 3 electrons.

So the electron configuration of strontium will be 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d³.

Learn how to draw: Vanadium orbital diagram

Next: Zirconium electron configuration

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Learnool.com was founded by Deep Rana, who is a mechanical engineer by profession and a blogger by passion. He has a good conceptual knowledge on different educational topics and he provides the same on this website. He loves to learn something new everyday and believes that the best utilization of free time is developing a new skill.